在Python中的嵌套列表上循环。打印单个字母

发布于 2025-01-24 09:02:55 字数 757 浏览 0 评论 0原文

我正在尝试将每个元素从列表中删除，但是由于某种原因，它正在打印列表中每个元素的每个字符。我该如何纠正？

我当前的代码：

import pandas as pd

myList = ["apple", ["banana", "blueberry"], "strawberry", ""]
myNames = ["Peter", "John", "Sally", "Craig"]

for x, y in zip(myNames, myList):
    decision = {"name": x, "fruit": y, "data": pd.DataFrame()}
    globals()[x] = decision

    for d, v in zip(myNames, myList):

        if len(v) > 1:
            for i in range(len(v)):
                print(v[i])
        else:
            print(v)
            d["data"] = v

现在，输出是：

A
P
P
L
E

我不想要这个。我希望Apple成为一个元素，并浏览else子句。如果子句是['Banana'，'Blueberry']

我该怎么做？

原文

I am trying to get each elements out of the list, but for some reason, it is printing out each individual characters of each element within the list. How would I correct this?

My current code:

import pandas as pd

myList = ["apple", ["banana", "blueberry"], "strawberry", ""]
myNames = ["Peter", "John", "Sally", "Craig"]

for x, y in zip(myNames, myList):
    decision = {"name": x, "fruit": y, "data": pd.DataFrame()}
    globals()[x] = decision

    for d, v in zip(myNames, myList):

        if len(v) > 1:
            for i in range(len(v)):
                print(v[i])
        else:
            print(v)
            d["data"] = v

Right now, it's output is:

A
P
P
L
E

I do not want this. I want apple to be a single element and go through the else clause. The only element that should go through the if clause is ['banana','blueberry']

How would I do this?

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捎一片雪花 2025-01-31 09:02:55

您可以将多维列表更扁平到单维列表，其中具有以下递归实现，该递归实现使用isInstance函数来检查变量是否为类型列表，允许我们正确地使用字符串弄平列表：

myList = ['apple',['banana', 'blueberry'],'strawberry','']
def flatten(l):
    out = []
    for i in l:
        if isinstance(i,list): 
            out += flatten(i)
        else: 
            out.append(i)
    return out
print(flatten(myList))

You can flatten a multidimensional list to a single-dimensional list with the following recursive implementation that uses isinstance function to check whether a variable is of type list, allowing us to flatten lists with strings correctly:

myList = ['apple',['banana', 'blueberry'],'strawberry','']
def flatten(l):
    out = []
    for i in l:
        if isinstance(i,list): 
            out += flatten(i)
        else: 
            out.append(i)
    return out
print(flatten(myList))

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