更改孩子的本地矩阵，以弥补父级本地矩阵的缩放

发布于 2025-01-24 05:39:47 字数 937 浏览 3 评论 0原文

a＆lt; - b＆lt; - c-是当地矩阵的链。

如果我扩展locala，它也会影响worldb。我想warldb保持未量。

问题在于我只能编辑localb矩阵，而没有其他。因此，“ localb”必须在其世界坐标计算之前“未量化”。

伪代码

scale = 1 to 5

localA = mat4.idt() * R(Y, 45) * S(1, scale, scale) * T(0, 0, 0)
localB = mat4.idt() * R(Y, 45) * S(1, 1, 1) * T(1, 0, 0) // I can only edit this
localC = mat4.idt() * R(Y, 45) * S(1, 1, 1) * T(1, 0, 0)

worldA = localA
worldB = worldA * localB
worldC = worldB * localC

休息状态。没有额外的扩展，只有本地转换

locala缩放并缩放儿童

，这就是我希望它看起来像

原文

A <-- B <-- C - are chain of local matrices.

If I scale the localA, it also affects to the worldB. I want to warldB stays unscaled.

The problem is that I can only edit the localB matrix and nothing else. Thus, 'localB' must be "unscaled" before its world coordinate calculated.

Pseudocode

scale = 1 to 5

localA = mat4.idt() * R(Y, 45) * S(1, scale, scale) * T(0, 0, 0)
localB = mat4.idt() * R(Y, 45) * S(1, 1, 1) * T(1, 0, 0) // I can only edit this
localC = mat4.idt() * R(Y, 45) * S(1, 1, 1) * T(1, 0, 0)

worldA = localA
worldB = worldA * localB
worldC = worldB * localC

Rest state. No extra scaling, just local to world conversion