将REGEXP构造函数转换为与Safari兼容的

发布于 2025-01-24 04:29:10 字数 379 浏览 3 评论 0原文

我有这个正则构造的模式，我将字符串变量传递到。这在Chrome中非常有效，但在Safari中不起作用。

有没有办法将此代码转换为在浏览器中兼容？谢谢你！

(e = e
  .split(new RegExp("(?<!\\w)" + t[l] + "(?!\\w)(?![^\\[\\]]*\\])", "gm"))
  .join(n)),
  1 == caseinsensitive &&
    (e = e.replace(
      new RegExp("(?<!\\w)" + t[l] + "(?!\\w)(?![^\\[\\]]*\\])", "gmi"),
      "[$&](" + n + ")"
    ));

原文

I have this regexp constructed pattern I'm passing a string variable to. This works perfectly in Chrome, but won't work in Safari.

Is there a way I might be able to convert this code to be compatible across browsers? Thank you!

(e = e
  .split(new RegExp("(?<!\\w)" + t[l] + "(?!\\w)(?![^\\[\\]]*\\])", "gm"))
  .join(n)),
  1 == caseinsensitive &&
    (e = e.replace(
      new RegExp("(?<!\\w)" + t[l] + "(?!\\w)(?![^\\[\\]]*\\])", "gmi"),
      "[amp;](" + n + ")"
    ));

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自控 2025-01-31 04:29:10

您可以使用

(e = e
  .split(new RegExp("(?!\\B\\w)" + t[l] + "(?!\\w)(?![^\\][]*])", "g"))
  .join(n)),
  1 == caseinsensitive &&
    (e = e.replace(
      new RegExp("(?!\\B\\w)" + t[l] + "(?!\\w)(?![^\\][]*])", "gi"),
      "[amp;](" + n + ")"
    ));

（？！\ b \ w）负面lookahead如果下一个char是一个字char，则需要一个单词边界位置。否则，如果下一个char不是字char，则无需单词边界。

You can use

(e = e
  .split(new RegExp("(?!\\B\\w)" + t[l] + "(?!\\w)(?![^\\][]*])", "g"))
  .join(n)),
  1 == caseinsensitive &&
    (e = e.replace(
      new RegExp("(?!\\B\\w)" + t[l] + "(?!\\w)(?![^\\][]*])", "gi"),
      "[amp;](" + n + ")"
    ));

The (?!\B\w) negative lookahead requires a word boundary position if the next char is a word char. Else, if the next char is not a word char, no word boundary is required.

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