在递归中仅应用一次条件
我只想在防护中应用一次条件。我的数据结构如下,
stages = {"stage_1": False, "stage_2":False, "stage_3":False,"state_4": False}
我想从中随机选择任何阶段,然后将状态更改为true。但是,当真实阶段的总数为3时,我想随机将真实阶段更改为false。但是只有一次。然后,它应该继续将阶段转为true。当所有4个阶段都是正确的时。递归过程停止。 我该怎么做? 我尝试了以下代码。但这还不完整。
def process(stages):
all_stages = [stage for stage, status in stages.items() if status == False]
if len(all_stages) !=0:
print(all_stages)
select_ = random.choice(all_stages)
print("\tselected stage: ",select_)
stages[select_] = True
process(stages)
else:
print("Done")
print(stages)
process(stages)
这在不添加额外条件的情况下起作用。我尝试了以下一个。但这不起作用
def process(stages):
all_stages = [stage for stage, status in stages.items() if status == False]
if len(all_stages) !=0:
print(all_stages)
select_ = random.choice(all_stages)
print("\tselected stage: ",select_)
stages[select_] = True
if len(all_stages) == 1:
select_ = random.choice([stage for stage, status in stages.items() if status == True])
stages[select_] = False
process(stages)
else:
print("Done")
print(stages)
process(stages)
I want to apply a condition inside a resursion only once. My data structure looks as follows
stages = {"stage_1": False, "stage_2":False, "stage_3":False,"state_4": False}
I want to pick any stage randomly from it and change the status to True. But when total number of true stage is 3 I want to randomly change a True stage to False. But only once. Then it should continue to turn stages in to True. When all 4 stages are true. The recursion process stops.
How can I do that ?
I have tried the following code. but it is not complete.
def process(stages):
all_stages = [stage for stage, status in stages.items() if status == False]
if len(all_stages) !=0:
print(all_stages)
select_ = random.choice(all_stages)
print("\tselected stage: ",select_)
stages[select_] = True
process(stages)
else:
print("Done")
print(stages)
process(stages)
This works without adding that extra condition. I have tried the following one. But that does not work
def process(stages):
all_stages = [stage for stage, status in stages.items() if status == False]
if len(all_stages) !=0:
print(all_stages)
select_ = random.choice(all_stages)
print("\tselected stage: ",select_)
stages[select_] = True
if len(all_stages) == 1:
select_ = random.choice([stage for stage, status in stages.items() if status == True])
stages[select_] = False
process(stages)
else:
print("Done")
print(stages)
process(stages)
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代码是@noblockhit的建议
the code is the suggestion from @NoBlockhit
与许多递归问题一样,在功能调用中添加状态将对您有很大帮助。
考虑对
process_internal()
进行内部呼吁,该将获得递归的当前状态,无论是阶段0(false -> true),阶段1(true - > false)还是阶段2 (false--> true)。As with many recursion problems, adding a state to your function call will help you a lot.
Consider making an inner call to
process_internal()
that would get the current state of the recursion, whether it's stage 0 (False -> True), stage 1 (True -> False) or stage 2 (False -> True).您可以将一个全局变量添加为标志,要获得的标志,您已经将一个变量设置为false,或者添加一个可选参数,例如rectionTofalse = false
当您最终将一个设置为False时,将其设置为True。
You could add a global variable as a flag to get, wheather you already set one back to False, or add an optional parameter like returnedToFalse=False
And set it to true when you eventually set one to false already.