在Python中，您如何注释一个接受固定参数以及许多其他参数的函数？
从我的理解来看，在Python中，省略号让您注释一个具有多数参数的函数（在此处找到的文档）。这是我想做的示例：
from typing import Callable, Any
def foo(first: str, *rest: Any):
print(rest)
return first
def call(f: Callable[[str, ...], str]):
f("Hello", 1, None, True)
print(call(foo))
python（或至少，佩莱斯）不喜欢省略号（“ ...”在此上下文中不允许）：
我尝试使用python 3.10的paramspec s，但是）似乎说它们用于其他目的，我无法说出这些目的是什么。这是我尝试过的：
from typing import Any, Callable, Concatenate, ParamSpec
P = ParamSpec("P")
def foo(first: str, *rest: Any):
print(rest)
return first
def call(f: Callable[Concatenate[str, P], str]):
f("Hello", 1, None, True)
print(call(foo))
Python（或至少是Pylance）似乎反映出它们并不是要使用这种方式：
rel =“ nofollow noreferrer”>
In Python, from my understanding, the ellipsis lets you annotate a function that has any number of arguments (documentation found here). Here's an example of what I'd like to do:
from typing import Callable, Any
def foo(first: str, *rest: Any):
print(rest)
return first
def call(f: Callable[[str, ...], str]):
f("Hello", 1, None, True)
print(call(foo))
Python (or, at least, Pylance) doesn't like the ellipsis ("..." not allowed in this context): 
I've tried to use Python 3.10's ParamSpecs, but the documentation on them (including PEP 612) seems to say they're used for other purposes, and I can't tell what those purposes are. Here's what I've tried:
from typing import Any, Callable, Concatenate, ParamSpec
P = ParamSpec("P")
def foo(first: str, *rest: Any):
print(rest)
return first
def call(f: Callable[Concatenate[str, P], str]):
f("Hello", 1, None, True)
print(call(foo))
Python (or, at least, Pylance) seems to reflect that they aren't meant to be used this way: 
How do I annotate a function like this, that knows the type of one or more of its arguments and accepts any number of other arguments anyway?
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您可以使用
__调用__在协议上键入任意功能签名。You can type arbitrary function signatures using
__call__on aProtocol