包含拼写错误的单词的类似子句中的文本搜索

Question

我们需要从免费文本子句中提取一些信息。让我们认为我们有一个关于AA船离开港口而去另一个港口的条款。相同的含义可以通过几种方式表达出来：

    The Ship A departed from the Port X on Monday, to reach Port Y.
    The ship A left the Port X on Monday to reach Port Y.
    The Ship A arrived to Port Y, it left Port X on Monday.
    Port Y will be visited by Ship A which left Port X on Monday.

作者也可能会拼错字：

   departed -> deported, dearted, depared, departeed, deparded
   reach -> reaach, rech, rreach, reac
   arrived -> arived, arivved, arrivd 

那么从这些条款中提取“ a shaph a”，“ a a a”，“ port x”，“ port y”，“ port y”的最佳方法是什么？ 编程语言是Java。 我们应该使用Reqular表达式或Lucene Fuzzy Search或Elasticsearch等。 还是它们的某种组合？

谢谢

Answer 1

该程序在示例字符串中找到所需的信息，并以正确的顺序列出。它需要进一步努力应对失误。我们还可以扩大日期的日期以接受日期。

import java.util.regex.*;
public class HelloWorld{

public static void main(String []args){
    System.out.println(getPorts("The Ship A departed from the Port X on Monday, to reach Port Y."));
    System.out.println(getPorts("The ship A left the Port X on Monday to reach Port Y."));
    System.out.println(getPorts("The Ship A arrived to Port Y, it left Port X on Monday."));
    System.out.println(getPorts("Port Y will be visited by Ship A which left Port X on Monday."));
     }
     
     public static String getPorts(String sentence){
         String port1 = "unknown";
         String port2 = "unknown";
         String ship = "unknown";
         String day = "unknown";
         Pattern pattern;
         if (sentence.matches(".*(arriv|reach|visit).*(left|depart).*")) {
            pattern = Pattern.compile("(?<port2>[Pp]ort\\s\\w+).*(?<port1>[Pp]ort\\s\\w+)");} 
         else if (sentence.matches(".*(left|depart).*(arriv|reach|visit).*")) {
            pattern = Pattern.compile("(?<port1>[Pp]ort\\s\\w+).*(?<port2>[Pp]ort\\s\\w+)");}
      else { return "not matched";}
      Matcher matcher = pattern.matcher(sentence);
      while (matcher.find()) {
          port2 = matcher.group("port2");
          port1 = matcher.group("port1");
      }
      pattern = Pattern.compile("(?<ship>[Ss]hip\\s\\w+)");
      matcher = pattern.matcher(sentence);
      while (matcher.find()) {
          ship = matcher.group("ship");
      }
      pattern = Pattern.compile("(?<day>(Mon|Tues?|Wed(nes)?|Thu(rs)?|Fri|Sat(ur)?|Sun)(day)?)");
      matcher = pattern.matcher(sentence);
      while (matcher.find()) {
          day = matcher.group("day");
      }
      return ship + " sailing from " + port1 + " to " + port2 + " on " + day +"." ;
}   
}

输出

Ship A sailing from Port X to Port Y on Monday.
ship A sailing from Port X to Port Y on Monday.
Ship A sailing from Port X to Port Y on Monday.
Ship A sailing from Port X to Port Y on Monday.

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