正则是从字符串过滤日期时间的时间

Question

要求：我正在收到带有模板的电子邮件，我需要从电子邮件中过滤一些文本。我将所有电子邮件主体文本转换为字符串。

电子邮件文本看起来像这样：

some body text which I don't need 

Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST description - this should be logged as a comment.  --- This is the part I need

ABC Company Australia | XYZ St | Sydney NSW 2000

我正在考虑拥有一个以下等级，该正则在

• “讨论”
• DateTime格式，以“ 26/04/2022/2：48 PM UTC+10/ABC用户 -
• 下行寻找 下一行直到我们找到这一行 - “ ABC Company Australia | XYZ ST | Sydney NSW 2000”地址

吗？有人可以帮忙言论吗？

tia。

Answer 1

如果OP感兴趣的内容只是足够的内容，那么以下等级已经足够了... <代码>/讨论：\ n [a-za-z] {1,3} \ s+\ d {2} \/\ d {2} \/\ d {4}。 。*）/

const multilineMail = `Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST description - this should be logged as a comment.  --- This is the part I need

ABC Company Australia | XYZ St | Sydney NSW 2000`;


// see ... [https://regex101.com/r/v8FXCA/3]
const regXMailContent =
  /Discussion:\n[a-zA-Z]{1,3}\s+\d{2}\/\d{2}\/\d{4}.*\n+(?<content>.*)/;

console.log(
  regXMailContent.exec(multilineMail)?.groups?.content
);

如果公司的页脚必须完全匹配，则必须像以下内容一样使其成为上述正则派对的一部分。 > /讨论：\ n [a-za-z] {1,3} \ s+\ d {2} \/\ d {2} \/\ d {2} \/\ d {4}。*\ n+（？＆lt;内容＆gt;。*）\ n+ABC公司澳大利亚\ | xyz st \ |悉尼新南威尔士州2000/

const multilineMail = `Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST description - this should be logged as a comment.  --- This is the part I need

ABC Company Australia | XYZ St | Sydney NSW 2000`;


// see ... [https://regex101.com/r/v8FXCA/4]
const regXMailContent =
  /Discussion:\n[a-zA-Z]{1,3}\s+\d{2}\/\d{2}\/\d{4}.*\n+(?<content>.*)\n+ABC Company Australia \| XYZ St \| Sydney NSW 2000/;

console.log(
  regXMailContent.exec(multilineMail)?.groups?.content
);

如果OP也要保存日期和用户，则将增强最初提供的正则拨号，例如...

• <代码>/讨论：\ n（？ ＆lt; content＆gt;。
• n+（ ？ ：\ n（？ \/\ s*（？＆lt; user＆gt;。*？） - ？\ s*\ n+（？

const multilineMail = `Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST description - this should be logged as a comment.  --- This is the part I need

ABC Company Australia | XYZ St | Sydney NSW 2000`;


// see ... [https://regex101.com/r/v8FXCA/2]
const regXMailDateAndContent =
  /Discussion:\n(?<date>[a-zA-Z]{1,3}\s+\d{2}\/\d{2}\/\d{4}).*\n+(?<content>.*)/;

// see ... [https://regex101.com/r/v8FXCA/1]
const regXMailDateUserAndContent =
  /Discussion:\n(?<date>[a-zA-Z]{1,3}\s+\d{2}\/\d{2}\/\d{4}\/[^/]+)\/\s*(?<user>.*?)-?\s*\n+(?<content>.*)/;

console.log(
  regXMailDateAndContent.exec(multilineMail)?.groups
);
console.log(
  regXMailDateUserAndContent.exec(multilineMail)?.groups
);

.as-console-wrapper { min-height: 100%!important; top: 0; }

但是，在 的情况下，要提取的内容是多行文本， Regex必须具有公司页脚才能确定正确的匹配。 2ndly提供的正则是... /docuction：\ n [a-za-z ] {1,3} \ s+\ d {2} \/\ d {2} \/\ d {4}。*\ n+（？＆lt; content＆gt;（？ \ | xyz st \ |悉尼新南威尔士州2000/

const multilineMail = `Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST

description - this should be
logged as a comment.  --- This is

the part I need


ABC Company Australia | XYZ St | Sydney NSW 2000`;


// see ... [https://regex101.com/r/v8FXCA/5]
const regXMailMultilineContent =
  /Discussion:\n[a-zA-Z]{1,3}\s+\d{2}\/\d{2}\/\d{4}.*\n+(?<content>(?:.*\n)*)ABC Company Australia \| XYZ St \| Sydney NSW 2000/;

console.log(
  regXMailMultilineContent.exec(multilineMail)?.groups?.content
);

.as-console-wrapper { min-height: 100%!important; top: 0; }

以上所有以上的正则模式均使用 名为cathing groupt。

Answer 2

您可以尝试以下等级：

Discussion.*?\n+([A-Za-z]+ +(?:\d{2}\/){2}\d{4}\/\d+:\d+ +[^\n]+)(.*)?ABC Company Australia \| XYZ St \| Sydney NSW 2000

说明：

1. 讨论。
2. 。*？\ n+不断寻找其他单词，而newlines
3. （[a-za-z]++（？：\ d {2} \/）{2} {2} \ d {4 } \/\ d+：\ d++[^\ n]+）接下来，它会如下所述寻找日期格式。它将全部获取，直到它到达Newline [^\ n+]
4. （。*）？它将从上一个日期行中获取所有内容
5. abc Company澳大利亚\ | xyz st \ |悉尼新南威尔士州2000和
   每当找到这个时，结论匹配。
6. 在这里，我将日期格式保持在第1组和身体中
   第2组

demo

来源：

const regex = /Discussion.*?\n+([A-Za-z]+ +(?:\d{2}\/){2}\d{4}\/\d+:\d+ +[^\n]+)(.*)?ABC Company Australia \| XYZ St \| Sydney NSW 2000/gms;

const str = `some body text which I don't need 

Discussion:
Tue 26/04/2022/2:48 PM UTC+10/ ABC User-

TEST description - this should be logged as a comment.  --- This is the part I need

ABC Company Australia | XYZ St | Sydney NSW 2000
`;

var match = regex.exec(str);
if(match!=null){
console.log(match[1]);
console.log(match[2]);
}