如何使用MongoDB聚集管道将同一记录分为多组
我有两个收藏。
orgstructure(将其视为树结构)
示例文档:
{
"id": "org1",
"nodes": [
{
"nodeId": "root",
"childNodes": ["child1"]
},
{
"nodeId": "child1",
"childNodes": ["child2"]
},
{
"nodeId": "child2",
"childNodes": []
}
]
}
活动
示例文档:
[
{
"id":"A1",
"orgUnit": "root"
},
{
"id":"A2",
"orgUnit": "child1"
},
{
"id":"A3",
"orgUnit": "child2"
}
]
现在,我的期望是通过orgunit
将其分组也考虑孩子节点。
在这里,我不想进行查找,我需要将一个访问者文档视为输入,以便我可以使用该文档构建某种条件,以至于查询将返回以下结果。
预期的结果
[
{
"_id": "root",
"activities": ["A1","A2","A3"]
},
{
"_id": "child1",
"activities": ["A2","A3"]
},
{
"_id": "child2",
"activities": ["A3"]
}
]
询问类似的汇总查询。
{
"$group": {
"_id": {
"$switch": {
"branches": [
{
"case": {"$in": ["$orgUnit",["root","child1","child2"]]},
"then": "root"
},
{
"case": {"$in": ["$orgUnit",["child1","child2"]]},
"then": "child1"
},
{
"case": {"$in": ["$orgUnit",["child2"]]},
"then": "child2"
}
],
"default": null
}
}
}
}
因此,我会提前
I have a two collections.
OrgStructure (visualise this as a tree structure)
Example Document:
{
"id": "org1",
"nodes": [
{
"nodeId": "root",
"childNodes": ["child1"]
},
{
"nodeId": "child1",
"childNodes": ["child2"]
},
{
"nodeId": "child2",
"childNodes": []
}
]
}
Activity
Example Document:
[
{
"id":"A1",
"orgUnit": "root"
},
{
"id":"A2",
"orgUnit": "child1"
},
{
"id":"A3",
"orgUnit": "child2"
}
]
Now my expectation is to group activities by orgUnit
such a way that by considering the child nodes as well.
Here i don't want to do a lookup and i need to consider one OrgStructure document as an input, so that i can construct some condition using the document such a way that the query will return the below result.
Expected result
[
{
"_id": "root",
"activities": ["A1","A2","A3"]
},
{
"_id": "child1",
"activities": ["A2","A3"]
},
{
"_id": "child2",
"activities": ["A3"]
}
]
So im ecpecting an aggregate query something like this
{
"$group": {
"_id": {
"$switch": {
"branches": [
{
"case": {"$in": ["$orgUnit",["root","child1","child2"]]},
"then": "root"
},
{
"case": {"$in": ["$orgUnit",["child1","child2"]]},
"then": "child1"
},
{
"case": {"$in": ["$orgUnit",["child2"]]},
"then": "child2"
}
],
"default": null
}
}
}
}
Thanks in advance!
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评论(1)
您将需要2个步骤:
节点
。原始orgstructure
很难执行$ graphlookup
$ graphlookup
onnodes
集合以获取所有子节点。执行$查找
到活动
,并进行一些争吵。这是 mongo Playground 供您参考。
You will need 2 steps:
nodes
for recursive lookup. The originalOrgStructure
is hard to perform$graphLookup
$graphLookup
onnodes
collection to get all child nodes. Perform$lookup
toActivity
and do some wrangling.Here is the Mongo playground for your reference.