然后创建一个集合，然后用20000＆＃x2b之间的200个数字填充该集合; 1，然后继续打印出该集合内部的每个数字

Question

#include <iostream>
#include <set>
#include <cstdlib>
#include <ctime>
#include <algorithm>
#include <vector>

//Create a set object to store a set of 200 randomly generated numbers from 1 to 10000. Use the for_each function and an anonymous function to display all the even numbers in the set.

using namespace std;

template <typename t>
void prints(t even) {
    void prints(t even) {
        if (even % 2) == 0;
        cout << "All the even numbers in the set are: " << even;
    }
}

int main()
{
    srand(time(0));
    set<int> nums;
    for (int i = 0; i < 200; i++) {
        nums.insert(rand() % 10000 + 1);
    }
    int gt50 = count_if(nums.begin(), nums.end(), [](int n) {return (n % 2) == 0}); // this is the issue it says I need ;, but when I put it nothing works. 

    for_each(nums.begin(), nums.end(), prints<int>);
}

我不明白为什么在第32行的结尾，它要求我实施；当我这样做时，命令要结束一行，它仍然会给我同样的问题。无论我不明白为什么这是在做我使用的调试器，但找不到任何东西的事情。

Answer 1

如果运行编译器，它将向您显示几个错误：

所以，编译器告诉您问题和位置。

然后，在删除了问题问题并在for循环条件下纠正语义错误后，您将得到：

#include <iostream>
#include <set>
#include <cstdlib>
#include <ctime>
#include <algorithm>
#include <vector>

//Create a set object to store a set of 200 randomly generated numbers from 1 to 10000. Use the for_each function and an anonymous function to display all the even numbers in the set.

using namespace std;

template <typename t>
void prints(t even) {
    if ((even % 2) == 0) 
        cout << even << '\n';
}

int main()
{
    srand((unsigned int)time(0));
    set<int> nums;
    for (int i = 0; nums.size() < 200; i++) {
        nums.insert(rand() % 10000 + 1);
    }
    int gt50 = count_if(nums.begin(), nums.end(), [](int n) {return (n % 2) == 0; }); // this is the issue it says I need ;, but when I put it nothing works. 

    for_each(nums.begin(), nums.end(), prints<int>);
}

这将起作用。