在AS3中应用双色转换

Question

简而言之，我想将几​​个MovieClips设置为不同的特定颜色，然后在它们上涂上色调。

var color1 = new ColorTransform(); color1.color = 0x0000FF;
var color2 = new ColorTransform(); color2.color = 0x00FF00;
var color3 = new ColorTransform(); color3.color = 0xFFFF00;

thing1.transform.colorTransform = color1;
thing2.transform.colorTransform = color2;
thing3.transform.colorTransform = color3;

thing1.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0);
thing2.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0);
thing3.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0);

不幸的是，ColorTransform重置该值。有什么方法可以保持第一个颜色转换的价值？

Answer 1

您应该能够使用 colortransform.concat（）函数。

var color1 = new ColorTransform(); color1.color = 0x0000FF;
var color2 = new ColorTransform(); color2.color = 0x00FF00;
var color3 = new ColorTransform(); color3.color = 0xFFFF00;

color1.concat( new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0) );
color2.concat( new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0) );
color3.concat( new ColorTransform(1, 1, 1, 1, 0, 200, 150, 0) );

thing1.transform.colorTransform = color1;
thing2.transform.colorTransform = color2;
thing3.transform.colorTransform = color3;

本质上与（使用Math.min.min将偏移值固定为255）：

thing1.transform.colorTransform = new ColorTransform(1*1, 1*1, 1*1, 1*1, Math.min(0x00+0, 0xFF), Math.min(0x00+200, 0xFF), Math.min(0xFF+150, 0xFF), Math.min(0x00+0, 0xFF));
thing2.transform.colorTransform = new ColorTransform(1*1, 1*1, 1*1, 1*1, Math.min(0x00+0, 0xFF), Math.min(0xFF+200, 0xFF), Math.min(0x00+150, 0xFF), Math.min(0x00+0, 0xFF));
thing3.transform.colorTransform = new ColorTransform(1*1, 1*1, 1*1, 1*1, Math.min(0xFF+0, 0xFF), Math.min(0xFF+200, 0xFF), Math.min(0x00+150, 0xFF), Math.min(0x00+0, 0xFF));

或：

thing1.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0x00, 0xC8, 0xFF, 0x00);
thing2.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0x00, 0xFF, 0x96, 0x00);
thing3.transform.colorTransform = new ColorTransform(1, 1, 1, 1, 0xFF, 0xFF, 0x96, 0x00);

Answer 2

我找到了解决这个问题的解决方案。

如果我将对象设置为颜色，

var color1 = new ColorTransform(); color1.color = 0x0000FF;
thing1.transform.colorTransform = color1;

则可以编辑蓝色和绿色值，以获取所需的色彩

color1.blueOffset+=200;
color1.greenOffset+=150;

，然后在对象上使用colortransform设置新颜色

thing1.transform.colorTransform = color1;