如何在dict中调用下一个值？

Question

i used the dict

LEVEL_XP = {
   0: 0,
   1: 5,
   2: 13,
   3: 20
}

and the code

new_level = int(level)
for level_on, xp_needed in LEVEL_XP.items():
    i = LEVEL_XP[xp_needed]

    if 0 <= i:
       if xp != i:
          print('nothing')
          break
       else:
          new_level = int(level_on) + 1
          print('level up')
          break

    else:
       new_level = int(level)
       break

where i could call level and xp from database and it works fine. the problem is after i reach 13 xp, i dont level up to 2 and its printing nothing. i've found the reason that the xp_needed calls only 0 which is the first value in the dict. 如何获得代码考虑下一个值，该值是13在我级别1时？ 以及如果我喜欢将整个XP删除至0并使用级别1重新启动，则该怎么办，因此代码需要调用13为xp_needed接下来，不是5？

Answer 1

如何获得代码考虑下一个值...？

在下面使用循环时使用。
It takes advantage of experience being monotonic with level.
We can probe each [level + 1] element quite efficiently,
without having to visit the "tons" of levels you mentioned.
We only examine levels that could be relevant.

class Character:

    def __init__(self, level=0, xp=0):
        self.level = level
        self.xp = xp

    def __str__(self):
        return f'<Character: level {self.level}, xp {self.xp}>'

    def adjust_to_increased_experience(self, new_xp):
        assert new_xp >= self.xp
        assert new_xp >= LEVEL_XP[self.level]
        while LEVEL_XP.get(self.level + 1, math.inf) <= new_xp:
            self.level += 1
        self.xp = new_xp