寻求不寻求适当的位置？

发布于 2025-01-23 11:21:11 字数 616 浏览 2 评论 0原文

我有以下代码：

  file.open(fileName, ios::in | ios::out | ios::binary);
   // many lines later
  file.seekp(fooAddr, ios::beg);
  printf("foo_addr: %d\n", foo_addr);
  file.write((char*)fooStruct, sizeof(FooStruct));

我知道fooaddr由于printf而为128。但是，由于某些原因，当我在十六进制编辑器中打开目标文件时，第一个字节是在位置80写的。

这是可能的吗？还是我在程序中忽略了一些错误？

我想，对于上下文，我所有的文件操作都包裹在一个宏中，该宏检查是否file.goodbit不是0（真相），如果是，则该程序在打印错误后立即退出。

原文

I have the following code:

  file.open(fileName, ios::in | ios::out | ios::binary);
   // many lines later
  file.seekp(fooAddr, ios::beg);
  printf("foo_addr: %d\n", foo_addr);
  file.write((char*)fooStruct, sizeof(FooStruct));

I know that fooAddr is 128 due to the printf.
Yet, for some reason, when I open the target file in my hex editor, the first byte is written at location 80.

Is this possible? Or is there some bug I am overlooking in my program?

I guess, for context, all my file operations are wrapped in a macro that checks if file.goodbit is not 0 (truthy), and if so -- the program immediately exits after printing an error.

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