在没有连接的情况下重新编写查询。
我正在重写要替换的查询以删除 的连接:
SELECT *
FROM ADM_TRT AT
INNER JOIN UTILISATEUR U
ON U.UTI_ID = AT.UTI_ID
INNER JOIN
(
SELECT CM.MAI_ID
FROM CON_MAI CM
CONNECT BY CM.MAI_PER_RES = PRIOR CM.MAI_ID
START WITH CM.MAI_ID IN (
SELECT MAJ_ID
FROM DROIT_LOGIN
WHERE LOG_ID = 21543
)
) CON_MAI_FILTERED_ON_LOGIN
ON AT.TRT_MAI_ID = CON_MAI_FILTERED_ON_LOGIN.MAI_ID;
对于通过
part连接,我写了
WITH tree (MAI_ID,MAI_PER_RES, level1) AS (
SELECT MAI_PER_RES, MAI_ID, 1 as level1 FROM CON_MAI
UNION ALL
SELECT child.MAI_ID, child.MAI_PER_RES, parent.level1 + 1
FROM CON_MAI child --Line 20
JOIN tree parent
on parent.MAI_PER_RES = child.MAI_ID
)
SELECT MAI_ID FROM tree
这篇子查询。有人可以帮忙整合吗?
I am rewriting the query to replace to remove CONNECT BY
:
SELECT *
FROM ADM_TRT AT
INNER JOIN UTILISATEUR U
ON U.UTI_ID = AT.UTI_ID
INNER JOIN
(
SELECT CM.MAI_ID
FROM CON_MAI CM
CONNECT BY CM.MAI_PER_RES = PRIOR CM.MAI_ID
START WITH CM.MAI_ID IN (
SELECT MAJ_ID
FROM DROIT_LOGIN
WHERE LOG_ID = 21543
)
) CON_MAI_FILTERED_ON_LOGIN
ON AT.TRT_MAI_ID = CON_MAI_FILTERED_ON_LOGIN.MAI_ID;
For CONNECT BY
Part , I wrote this
WITH tree (MAI_ID,MAI_PER_RES, level1) AS (
SELECT MAI_PER_RES, MAI_ID, 1 as level1 FROM CON_MAI
UNION ALL
SELECT child.MAI_ID, child.MAI_PER_RES, parent.level1 + 1
FROM CON_MAI child --Line 20
JOIN tree parent
on parent.MAI_PER_RES = child.MAI_ID
)
SELECT MAI_ID FROM tree
But I am stuck to integrate this in subquery in the CONNECT BY
sub-query. Can someone please help to integrate this?
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看来您的递归逆转了递归的子查询,并且可以使用:
(未经测试,因为我没有您的表格或数据)
It looks like you have the recursion reversed in the recursive sub-query and can use:
(untested as I do not have your tables or data)