解析＆amp;在JavaScript中检查条件表达式

发布于 2025-01-23 02:05:44 字数 560 浏览 2 评论 0原文

我的字符串中有可变条件，因此：

（ @is_verified ='true'或@confirmation_needed！='true'）和@request_limit！='0'

这只是一个示例，并且有未知数的变量＆amp;案例。

每个变量都以 @ @
有时有括号值的ors和s和shiss的
引号，例如'xyz'，因此所有变量都可以视为字符串。
检查条件

JavaScript映射

const vars = {
 IS_VERIFIED: 'True',
 CONFIRMATION_NEEDED: 'True',
 REQUEST_LIMIT: '2'
}

始终使用=或！=我也有一个。我提出了很少的想法，但它们都太复杂了。是否有任何已知的简单方法，或者我必须从头开始创建一些东西？

感谢任何帮助，谢谢。

编辑：实现这一目标后，对我来说，下一个目标将显示哪些变量以某种方式破坏了状况。

原文

I have string that have variable conditions in it, like this:

(@IS_VERIFIED = 'True' OR @CONFIRMATION_NEEDED != 'True') AND @REQUEST_LIMIT != '0'

This is just an example and there are unknown number of variables & cases.

Every variable starts with @
There are ORs and ANDs with sometimes parenthesis
Values are always in quotation marks like 'xyz', so all can be considered strings.
Conditions are always checked with either = or !=

I also have a javascript map which holds all the variables like:

const vars = {
 IS_VERIFIED: 'True',
 CONFIRMATION_NEEDED: 'True',
 REQUEST_LIMIT: '2'
}

What I need to do is parse the condition string and check the values using the map above to reach a final result, true or false. I came up with few ideas but they were all too complicated. Is there any known, easy method for this or do I have to create something from scratch?

Any help is appreciated, thanks.

Edit: After achieving this, next goal for me will be showing which variables break the condition, somehow.

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纸短情长 2025-01-30 02:05:44

注意：`eval`提前解决方案，在使用此问题时要非常小心！

只需修改字符串为有效的JS表达式，然后使用eval。

const vars = {
  IS_VERIFIED: "True",
  CONFIRMATION_NEEDED: "True",
  REQUEST_LIMIT: "2",
};

const str = `(@IS_VERIFIED = 'True' OR @CONFIRMATION_NEEDED != 'True') AND @REQUEST_LIMIT != '0'`;

const evalStr = str
  .replaceAll("@", "vars.")
  .replaceAll("OR", "||")
  .replaceAll("AND", "&&")
  .replaceAll("!=", "!")
  .replaceAll("=", "===")
  .replaceAll("!", "!==");

const res = eval(evalStr);
console.log(res);

Caution: `eval` solution ahead, be very careful while using this!

Simply modify the string to be a valid JS expression and then use eval.

const vars = {
  IS_VERIFIED: "True",
  CONFIRMATION_NEEDED: "True",
  REQUEST_LIMIT: "2",
};

const str = `(@IS_VERIFIED = 'True' OR @CONFIRMATION_NEEDED != 'True') AND @REQUEST_LIMIT != '0'`;

const evalStr = str
  .replaceAll("@", "vars.")
  .replaceAll("OR", "||")
  .replaceAll("AND", "&&")
  .replaceAll("!=", "!")
  .replaceAll("=", "===")
  .replaceAll("!", "!==");

const res = eval(evalStr);
console.log(res);

回复收藏 0 原文

过期以后 2025-01-30 02:05:44

这是使用Regexp的片段：

let test = "@XYZ='True' AND @ABC='False'";

const regexp = /(@\w+)|(\'\w+\')/g;

const regexpResult = [...test.match(regexp)]
// Returns something like this:
// ["@XYZ", "'True'", "@ABC", "'False'"]

const vars = {};

for (let i = 0; i < regexpResult.length; i += 2) // We will be using two consecutive values at a time
{
  let keyName = regexpResult[i].replace("@", "");
  let keyValue = regexpResult[i+1].replaceAll("'", "");
  
  vars[keyName] = keyValue;
}

// OUTPUT of "vars":
// {
//   XYZ: "True",
//   ABC: "False"
// }

我希望这使您了解如何解决问题。

Here is a snippet using RegExp:

let test = "@XYZ='True' AND @ABC='False'";

const regexp = /(@\w+)|(\'\w+\')/g;

const regexpResult = [...test.match(regexp)]
// Returns something like this:
// ["@XYZ", "'True'", "@ABC", "'False'"]

const vars = {};

for (let i = 0; i < regexpResult.length; i += 2) // We will be using two consecutive values at a time
{
  let keyName = regexpResult[i].replace("@", "");
  let keyValue = regexpResult[i+1].replaceAll("'", "");
  
  vars[keyName] = keyValue;
}

// OUTPUT of "vars":
// {
//   XYZ: "True",
//   ABC: "False"
// }

I hope this gives you an idea about how to solve your problem.

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