如何通过编程iOS中使用新的phpickerviewController从照片中加载图像？

发布于 2025-01-22 22:13:36 字数 464 浏览 0 评论 0原文

我想使用新的phpickerviewController从照片中选择图像，并且我想直接打开phpickerviewcontroller当我的控制器加载时。

像这样

“像这样”

import UIKit
class ViewController: UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()
         // Do any additional setup after loading the view.
         // TODO: - Here I want PhotoPicker
       }
    }

原文

I want to select an image from photos using new PHPickerViewController and I want to open PHPickerViewController directly when my controller is load.

Like this

import UIKit
class ViewController: UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()
         // Do any additional setup after loading the view.
         // TODO: - Here I want PhotoPicker
       }
    }

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烟花肆意 2025-01-29 22:13:36

您可以在要放置phpicker时调用此方法`openphpicker（）`。

您也可以使用此代码。为了打开新 phpicker 。
有关wwdc21中的phpicker的更多了解， href =“ https://developer.apple.com/videos/play/wwdc2021/10046/” rel =“ noreferrer”> phpicker wwdc21视频
wwdc phpicker phpicker笔记.com/notes/wwdc20/10652/“ rel =“ noreferrer”> phpicker notes

import Photos
import PhotosUI


// MARK: - PHPicker Configurations (PHPickerViewControllerDelegate)
extension ViewController: PHPickerViewControllerDelegate {
    func picker(_ picker: PHPickerViewController, didFinishPicking results: [PHPickerResult]) {
         picker.dismiss(animated: true, completion: .none)
         results.forEach { result in
               result.itemProvider.loadObject(ofClass: UIImage.self) { reading, error in
               guard let image = reading as? UIImage, error == nil else { return }
               DispatchQueue.main.async {
                   self.profilePictureOutlet.image = image
                   // TODO: - Here you get UIImage
               }
               result.itemProvider.loadFileRepresentation(forTypeIdentifier: "public.image") { [weak self] url, _ in
                // TODO: - Here You Get The URL
               }
          }
       }
  }

   /// call this method for `PHPicker`
   func openPHPicker() {
       var phPickerConfig = PHPickerConfiguration(photoLibrary: .shared())
       phPickerConfig.selectionLimit = 1
       phPickerConfig.filter = PHPickerFilter.any(of: [.images, .livePhotos])
       let phPickerVC = PHPickerViewController(configuration: phPickerConfig)
       phPickerVC.delegate = self
       present(phPickerVC, animated: true)
   }
}

you can call this method `openPHPicker()` when ever you want to place your PHPicker.

You can use this code also. for opening new PHPicker.
For More Knowledge about PHPicker in WWDC21 PHPicker WWDC20 Video and PHPicker WWDC21 Video
WWDC PHPicker Notes PHPicker Notes

import Photos
import PhotosUI


// MARK: - PHPicker Configurations (PHPickerViewControllerDelegate)
extension ViewController: PHPickerViewControllerDelegate {
    func picker(_ picker: PHPickerViewController, didFinishPicking results: [PHPickerResult]) {
         picker.dismiss(animated: true, completion: .none)
         results.forEach { result in
               result.itemProvider.loadObject(ofClass: UIImage.self) { reading, error in
               guard let image = reading as? UIImage, error == nil else { return }
               DispatchQueue.main.async {
                   self.profilePictureOutlet.image = image
                   // TODO: - Here you get UIImage
               }
               result.itemProvider.loadFileRepresentation(forTypeIdentifier: "public.image") { [weak self] url, _ in
                // TODO: - Here You Get The URL
               }
          }
       }
  }

   /// call this method for `PHPicker`
   func openPHPicker() {
       var phPickerConfig = PHPickerConfiguration(photoLibrary: .shared())
       phPickerConfig.selectionLimit = 1
       phPickerConfig.filter = PHPickerFilter.any(of: [.images, .livePhotos])
       let phPickerVC = PHPickerViewController(configuration: phPickerConfig)
       phPickerVC.delegate = self
       present(phPickerVC, animated: true)
   }
}

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