替换为字母位置

发布于 2025-01-22 21:23:13 字数 995 浏览 1 评论 0原文

编写一个赋予字符串的函数，将每个字母替换为字母中的位置。如果文本中的任何内容不是字母，请忽略它，不要退还它。 a是1，b为2等。例如：字母表（“日落设置为十二O'时钟。”）应返回“ 20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 1 15 3 12 15 3 11”作为弦。

std::string alphabet_position(std::string message)
{ 
    message.erase(std::remove_if(message.begin(), message.end(), isspace), message.end());

    std::ostringstream os;
    for (auto const & c : message)
    {
        char c_lower = std::tolower(c);
        if (c_lower < 'a' || c_lower > 'z')  continue;
        int pos = c_lower - 'a' + 1 ;
        os << pos;
        os << ' ';
    }


    return os.str();
}


int main(){ 

  std::string text; 
  std::cout<<"Enter a phrase :"<<std::endl; 
  std::cin>>text; 
  std::string s_out = alphabet_position(text);
  std::cout<<"the alphabet positions :"<<s_out<<std::endl;


    return 0;
}

我真的在为这个挑战而苦苦挣扎。这里的问题是，当我输入短语时，代码将仅在第一个空间之前给我字母的字母位置。例子：输入：日落设置为十二O'时钟。输出：20 8 5

原文

Write a function that is given a string, replace every letter with its position in the alphabet. If anything in the text isn't a letter, ignore it and don't return it. a being 1, b being 2, etc.As an example:
AlphabetPosition("The sunset sets at twelve o' clock.")
Should return "20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11" as a string.

std::string alphabet_position(std::string message)
{ 
    message.erase(std::remove_if(message.begin(), message.end(), isspace), message.end());

    std::ostringstream os;
    for (auto const & c : message)
    {
        char c_lower = std::tolower(c);
        if (c_lower < 'a' || c_lower > 'z')  continue;
        int pos = c_lower - 'a' + 1 ;
        os << pos;
        os << ' ';
    }


    return os.str();
}


int main(){ 

  std::string text; 
  std::cout<<"Enter a phrase :"<<std::endl; 
  std::cin>>text; 
  std::string s_out = alphabet_position(text);
  std::cout<<"the alphabet positions :"<<s_out<<std::endl;


    return 0;
}

I am really struggling with this challenge. The Issue here is that when I enter a phrase, the code will give me only the alphabet positions of the letters before the first space.
example:
Input: The sunset sets at twelve o' clock.
Output: 20 8 5

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