云飞行编码比赛 - 火星漫游者

Question

做火星漫游者编码问题，并且陷入了2级。试图调试，但我看不到它，它不会让我进步直到当前级别完成。

问题描述如下：

以一定的转向角度驾驶一定距离后，计算漫游者的位置和方向。

输入：轴距，距离，方向盘（2个小数小数） 输出：X，Y，新界面角

示例： 在：1.00 1.00 30.00 出局：0.24 0.96 28.65

有人知道某些步行，解决方案等的任何链接还是更多示例？

底部有一个指向编码问题的图像链接，

请感谢

https：/ /训练/1212/Play

## Level 1 - calculate the turn radius ##
## level1 2 - calculate new position and angle
import math


## solution works for this data
WHEELBASE = 1.00
DISTANCE = 1.00
STEERINGANGLE = 30.00

#WHEELBASE = 1.75
#DISTANCE = 3.14
#STEERINGANGLE = -23.00


def calculateTurnRadius(wheelbase, steeringangle):
    return round(wheelbase / math.sin(math.radians(steeringangle)), 2)

def calculateNewDirection(wheelbase, steeringangle, distance):
    turnRadius = calculateTurnRadius(wheelbase, steeringangle)
    theta = distance / turnRadius

    #brings theta to within a 180 arc
    while theta >= math.pi * 2:
        theta -= math.pi * 2

    while theta < 0:
        theta += math.pi * 2

    # calculate theta with basic sin and cos trig
    x = turnRadius - (math.cos(theta) * turnRadius)
    y = math.sin(theta) * turnRadius
    
    x = abs(round(x, 2))
    y = round(y, 2)
    theta = math.degrees(theta)

    theta = round(theta, 2)

    return x, y, theta


print(f"Turn Radius = {calculateTurnRadius(WHEELBASE, STEERINGANGLE)}")
print(f"{calculateNewDirection(WHEELBASE, STEERINGANGLE, DISTANCE)}")

Turn Radius = 2.0
(0.24, 0.96, 28.65)

 


  [1]: https://i.sstatic.net/tDY2u.jpg

Answer 1

我并没有真正看过您的代码，但是我从1级到4的解决方案都得到了解决方案。因此，这是我的2级代码。

import math

def turn_radius(wheel_base, steering_angle):
    radius: float = wheel_base/math.sin(math.radians(steering_angle))
    print (f"{radius:.2f}")

    return radius

def get_position(distance, steering_angle, radius):
    angle = (distance*180)/(math.pi*radius)
    y = (math.sin(math.radians(angle)) * radius)
    x = radius - (math.cos(math.radians(angle)) * radius)

    while angle < 0:
        angle = 360 + angle
    
    if angle == 360:
        angle = 0

    print(f"{x:.2f} {y:.2f} {angle:.2f}")

if __name__ == "__main__":
    wheel_base = 2.7
    distance = 45
    steering_angle = -34

    if steering_angle == 0:
        steering_angle = 360

    radius = turn_radius(wheel_base ,steering_angle)
    get_position(distance, steering_angle, radius)

Answer 2

我也卡住了，但是到目前为止，我对前两个输入有效：

import math

WheelBase, Distance, SteeringAngle = 1, 1, 30.00
WheelBase, Distance, SteeringAngle = 2.13, 4.30, 23.00

WheelBase = float(WheelBase)
Distance = float(Distance)
SteeringAngle = float(SteeringAngle)

TurnRadius = abs(WheelBase / math.sin(math.pi * (SteeringAngle) / 180))

NewDirection = 180 * (Distance / TurnRadius) / math.pi

chord = 2 * TurnRadius * math.sin(math.pi * NewDirection / 360)

y = TurnRadius * math.sin(math.pi * (NewDirection) / 180)

x = math.sqrt(chord ** 2 - y ** 2)

print(round(x, 2), round(y, 2), round(NewDirection, 2))

print(chord)
print(math.sqrt(x ** 2 + y ** 2))