为什么两个魔术模拟实例在ID中有所不同？

发布于 2025-01-22 14:29:42 字数 1777 浏览 2 评论 0原文

阅读本教程后，我正在尝试使用Patch（）将模拟注入呼叫： https://kimsereylam.com/python/2021/03/03/how-to-to-poth-to-path-to-patch-patch-in-patch-in-python-unittest.html一下期望模拟ID与实际不同。

这是要说明的代码段：

my_class.py

class MyClass:
    def __init__(self):
        self.value = 5

run.py

from my_class import MyClass

def call_first():
    o = MyClass()
    print(o)
    call_second(o)
    
def call_second(myclass):
    print("second is called")
    print(myclass)

main。 PY

from unittest.mock import patch
from my_class import MyClass
from run import call_first, call_second

with patch("run.MyClass") as myclass_mock:
    print(myclass_mock)
    print(call_first())
with patch("run.call_second") as call_second_mock:
    call_second_mock.assert_called_once_with(myclass_mock)

输出是：

<MagicMock name='MyClass' id='140711608367712'>
<MagicMock name='MyClass()' id='140711598743312'>
second is called
<MagicMock name='MyClass()' id='140711598743312'>
None
Traceback (most recent call last):
  File "main.py", line 9, in <module>
    call_second_mock.assert_called_once_with(myclass_mock)
  File "/usr/lib/python3.8/unittest/mock.py", line 924, in assert_called_once_with
    raise AssertionError(msg)
AssertionError: Expected 'call_second' to be called once. Called 0 times.

我错过了什么？我正在尝试使用patch（），因此我可以模拟call_first（）内实例化并传递给call_second（）的myClass（）对象。

原文

I am trying to use patch() to inject mock into a call after reading this tutorial: https://kimsereylam.com/python/2021/03/19/how-to-use-patch-in-python-unittest.html, but the expect mock ID is different than actual.

Here is snippet of code to illustrate:

my_class.py

class MyClass:
    def __init__(self):
        self.value = 5

run.py

from my_class import MyClass

def call_first():
    o = MyClass()
    print(o)
    call_second(o)
    
def call_second(myclass):
    print("second is called")
    print(myclass)

main.py

from unittest.mock import patch
from my_class import MyClass
from run import call_first, call_second

with patch("run.MyClass") as myclass_mock:
    print(myclass_mock)
    print(call_first())
with patch("run.call_second") as call_second_mock:
    call_second_mock.assert_called_once_with(myclass_mock)

The output is:

<MagicMock name='MyClass' id='140711608367712'>
<MagicMock name='MyClass()' id='140711598743312'>
second is called
<MagicMock name='MyClass()' id='140711598743312'>
None
Traceback (most recent call last):
  File "main.py", line 9, in <module>
    call_second_mock.assert_called_once_with(myclass_mock)
  File "/usr/lib/python3.8/unittest/mock.py", line 924, in assert_called_once_with
    raise AssertionError(msg)
AssertionError: Expected 'call_second' to be called once. Called 0 times.

What did I miss? I am trying to use patch() so I can mock the MyClass() object that is instantiated inside call_first() and passed to call_second().

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弃爱 2025-01-29 14:29:42

with patch("run.MyClass") as myclass_mock:
    with patch("run.call_second") as call_second_mock:
        #print(myclass_mock)
        instance = myclass_mock.return_value
        print(instance)
        print(call_first())
        call_second_mock.assert_called_once_with(instance)

我需要使用.return_value来获取类实例的magionmock
我应该模拟call_second首先

with patch("run.MyClass") as myclass_mock:
    with patch("run.call_second") as call_second_mock:
        #print(myclass_mock)
        instance = myclass_mock.return_value
        print(instance)
        print(call_first())
        call_second_mock.assert_called_once_with(instance)