生成许多序列
我想生成以下序列：
myseq <- seq(0,0.1, by=0.0001)
myseq <- seq(0,0.2, by=0.0001)
myseq <- seq(0,0.3, by=0.0001)
.
.
.
myseq <- seq(0,1, by=0.0001)
myseq <- seq(0.1,0.2, by=0.0001)
myseq <- seq(0.1,0.3, by=0.0001)
myseq <- seq(0.1,0.4, by=0.0001)
.
.
.
myseq <- seq(0.9,1, by=0.0001) # I want to stop here.
我尝试手动以下代码，但我的直觉似乎并不正确：
#Counters
from=0
to=0.1
a = seq(from, to, by=0.001)
#I execute following to check if my intuition is correct.
from=case_when(to<=0.9 ~ from,
to==1 ~ from+0.1)
to=case_when(to<0.9 ~ to+0.1,
to==1 ~ 1)
a = seq(from, to, by=0.0001)
I would like to generate following sequences:
myseq <- seq(0,0.1, by=0.0001)
myseq <- seq(0,0.2, by=0.0001)
myseq <- seq(0,0.3, by=0.0001)
.
.
.
myseq <- seq(0,1, by=0.0001)
myseq <- seq(0.1,0.2, by=0.0001)
myseq <- seq(0.1,0.3, by=0.0001)
myseq <- seq(0.1,0.4, by=0.0001)
.
.
.
myseq <- seq(0.9,1, by=0.0001) # I want to stop here.
I tried with following code manually but my intuition does not seem to be correct here:
#Counters
from=0
to=0.1
a = seq(from, to, by=0.001)
#I execute following to check if my intuition is correct.
from=case_when(to<=0.9 ~ from,
to==1 ~ from+0.1)
to=case_when(to<0.9 ~ to+0.1,
to==1 ~ 1)
a = seq(from, to, by=0.0001)
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使用seq 使用
combn创建seq's 的矩阵，和参数，然后在mapply创建序列列表。Use
combnto create a matrix ofseq'sfromandtoparameters, and then apply them onsequsingmapplyto create the list of sequences.