如何让我的C外壳认识到这是命令?
我在C上很新,但目前正在努力创建C程序以充当外壳接口。它应该接受命令,然后在单独的过程中执行每个命令。目前,我被困在试图让C认识到这是命令。我不确定该怎么做,似乎找不到任何有用的例子。
这是我的代码,它说的一切都不是有效的命令(“否CMD”)。有人知道为什么会发生这种情况吗? C是否无法识别它是execvp()函数中的命令,还是我需要为该特定目的实现某些内容?
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <errno.h>
#include <sys/types.h>
#include <sys/wait.h>
#define MAX_LINE 80
/* 80 chars per line per command */
int main(void) {
//char *args[MAX_LINE/2 + 1];
char *args = calloc(MAX_LINE, (MAX_LINE/2 +1));
const size_t sz = MAX_LINE;
pid_t pid;
/* command line (of 80) has max of 40 arguments*/
int should_run = 1;
while (should_run) {
printf("osh>"); //beginning of command line
fgets(args, sz, stdin); //gets the stdin
char *token = strtok(args, " \n"); //supposed to break str if it has a space or line and recognize there are 2 commands
printf("%s\n", token);
token = strtok(NULL," \n");
printf("%s\n", token);
pid_t parent = getpid();
pid = fork(); //forking child
if(pid == 0){ //if forking occurred
int status = execvp(&args[0], &args); //status of input, is it a command?
printf("%d", status);
printf("forked!");
if(status == -1) { //if cmd err, print
printf("no cmd");
return 1;
} else {
printf("line will be printed");
}
return 0;
}
fflush(stdout); //flush
/*
* After reading user input, the steps are :
* 1: fork a child process
* 2: the child process will invoke execvp()
* 3: parent process waits for the child to exit before
continuing
*/
}
exit(0);
/**
return to the operating system:
-exit this process
-flush all
*/
}
I am very new at C but am currently working on creating a C program to serve as a shell interface. It is supposed to accept commands and then execute each command in a separate process. I am currently stuck trying to get C to recognize that it is a command. I am unsure how to do this, and can't seem to find any useful examples.
Here is my code, it is saying that everything is not a valid command ("no cmd"). Does anyone have any idea why this would be occurring? Is C not able to recognize it is a command in the execvp() function or do I need to implement something for that specific purpose?
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <errno.h>
#include <sys/types.h>
#include <sys/wait.h>
#define MAX_LINE 80
/* 80 chars per line per command */
int main(void) {
//char *args[MAX_LINE/2 + 1];
char *args = calloc(MAX_LINE, (MAX_LINE/2 +1));
const size_t sz = MAX_LINE;
pid_t pid;
/* command line (of 80) has max of 40 arguments*/
int should_run = 1;
while (should_run) {
printf("osh>"); //beginning of command line
fgets(args, sz, stdin); //gets the stdin
char *token = strtok(args, " \n"); //supposed to break str if it has a space or line and recognize there are 2 commands
printf("%s\n", token);
token = strtok(NULL," \n");
printf("%s\n", token);
pid_t parent = getpid();
pid = fork(); //forking child
if(pid == 0){ //if forking occurred
int status = execvp(&args[0], &args); //status of input, is it a command?
printf("%d", status);
printf("forked!");
if(status == -1) { //if cmd err, print
printf("no cmd");
return 1;
} else {
printf("line will be printed");
}
return 0;
}
fflush(stdout); //flush
/*
* After reading user input, the steps are :
* 1: fork a child process
* 2: the child process will invoke execvp()
* 3: parent process waits for the child to exit before
continuing
*/
}
exit(0);
/**
return to the operating system:
-exit this process
-flush all
*/
}
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如果您查看
exec
函数系列的文档,您会注意到,仅当exec
失败时,功能才返回。这是因为exec
成功时,用调用程序完全替换了调用过程。您需要做的是,从父级进程(即获得从
fork
>的正值),通过waitpid
等待子进程。If you look at the documentation for the
exec
family of functions, you'll note that the functions only return if theexec
failed. That's becauseexec
, when successful, completely replaces the calling process with the invoked program.What you need to do is, from the parent process (i.e., the one that got a positive value returned from
fork
), wait on the child process viawaitpid
.