循环时可以使用哪个循环进行？

发布于 2025-01-22 09:30:35 字数 859 浏览 0 评论 0原文

我想知道如何使用循环凝结此代码。这是（i）变量定义的重复序列（ii）时循环条件...（iii）变量增量

list_main = []
x1 = 1
while x1<= n:
    x2 = x1
    while x2 <= n:
        x3 = x2
        while x3 <= n:
#continue the sequence: x(i) = x(i-1) ; while x(i) <= n:
 
            list_ = [x1,x2,...]
            list_main.append(list_)
            x3 = x3 + 1
        x2 = x2 + 1
    x1 = x1 + 1

我想要这样的东西：

max_x = 10 #maximum number of 'x's
#code
list_ = [x1,x2,x3,x4,x5,x6,x7,x8,x9,x10]

edit

如果'x的数字为2，而n为5 ，然后我所需的输出，即，list_main是

list_main = [[1,1],[1,2],[1,3],[1,4],[1,5],[2,2],[2,3],[2,4],[2,5],[3,3],[3,4],[3,5],[4,4],[4,5],[5,5]]

'x的数量为3，n为3，那么我所需的输出是

list_main = [[1,1,1],[1,1,2],[1,1,3],[1,2,2],[1,2,3],[2,2,2],[2,2,3],[2,3,3],[3,3,3]]

原文

I want to know how to condense this code using loops. It is a repeated sequence of (i) variable definition (ii) while loop condition ...(iii) variable increment

list_main = []
x1 = 1
while x1<= n:
    x2 = x1
    while x2 <= n:
        x3 = x2
        while x3 <= n:
#continue the sequence: x(i) = x(i-1) ; while x(i) <= n:
 
            list_ = [x1,x2,...]
            list_main.append(list_)
            x3 = x3 + 1
        x2 = x2 + 1
    x1 = x1 + 1

I want something like this:

max_x = 10 #maximum number of 'x's
#code
list_ = [x1,x2,x3,x4,x5,x6,x7,x8,x9,x10]

Edit

If Number of 'x's is 2 and n is 5, then my desired output, i.e., list_main is

list_main = [[1,1],[1,2],[1,3],[1,4],[1,5],[2,2],[2,3],[2,4],[2,5],[3,3],[3,4],[3,5],[4,4],[4,5],[5,5]]

If the number of 'x's is 3 and n is 3, then my desired output is

list_main = [[1,1,1],[1,1,2],[1,1,3],[1,2,2],[1,2,3],[2,2,2],[2,2,3],[2,3,3],[3,3,3]]

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水染的天色ゝ 2025-01-29 09:30:35

如这个答案，您的问题可以这样解决：

max_x = 10
n = 5
values = []
i = 1
while i <= n:
    list_values.append(i)
    i = i + 1
count = [max_x] * n
list_main = list(unique_combinations_from_value_counts(values,count,max_x))

As pointed out in this answer, your problem can be solved like this:

max_x = 10
n = 5
values = []
i = 1
while i <= n:
    list_values.append(i)
    i = i + 1
count = [max_x] * n
list_main = list(unique_combinations_from_value_counts(values,count,max_x))

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