如何在子过程中更改ENV？
我不了解Popen子过程中ENV属性的价值。我想更改我正在运行的Python代码的虚拟环境。
示例
假设通过虚拟环境运行的名为subprocess_test.py的文件venv_main：
# subprocess_test.py
cmd = f"C:/home/._venv/Scripts/python example.py".split()
sp = subprocess.Popen(cmd, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, universal_newlines=True, cwd="/home", env = "___________")
try:
sp.wait(timeout=16)
run_output, run_error = sp.communicate()
except subprocess.TimeoutExpired:
sp.kill()
run_output, run_error = sp.communicate()
示例
import os
print(os.environ)
。 _venv/scripts 相反，它打印了subprocess_test.py执行的环境的详细信息，venv_main
也许env属性可以解决我的问题，但我不了解env属性如何工作，什么是什么环境的适当价值？
I do not understand the value of the env attribute in the Popen subprocess. I want to change the virtual environment of the python code I am running.
example
Suppose a file named subprocess_test.py which is run through virtual environment venv_main:
# subprocess_test.py
cmd = f"C:/home/._venv/Scripts/python example.py".split()
sp = subprocess.Popen(cmd, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, universal_newlines=True, cwd="/home", env = "___________")
try:
sp.wait(timeout=16)
run_output, run_error = sp.communicate()
except subprocess.TimeoutExpired:
sp.kill()
run_output, run_error = sp.communicate()
example.py
import os
print(os.environ)
It do not print the details of venv which Suprocess command takes .i.e, C:/home/._venv/Scripts instead It print the details of environment from which subprocess_test.py executes i.e., venv_main
Maybe env attribute can solve my problem But I do not understand how env attribute work and what is the appropriate value of env?
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env参数应为词典，其中键是env var名称。通常，您想制作os.environ的副本，然后对其进行修改（例如，通过更改path的值）以适合您的需求。这是一个常见问题解答。参见，例如，这个stackoverflow问题。The
envargument should be a dictionary where the key is the env var name. In general you want to make a copy ofos.environthen modify it (e.g., by changing the value ofPATH) to suit your needs. This is a FAQ. See, for example, this stackoverflow question.