创建具有所需尺寸和值跳过其他所有索引的矩阵的GO函数
我正在尝试编写一个创建矩阵的函数，用户可以在其中输入矩阵的尺寸以及其中的值。我设法获得了结果，但我注意到，在输入值时，函数忽略了每两个索引中的一个并用0填充它。
package main
import "fmt"
func makeMatrix(n int, m int) [][]int {
matrix := make([][]int, n)
for i := range matrix {
matrix[i] = make([]int, m)
}
fmt.Println("Enter elements : ")
for i := range matrix {
fmt.Scanf("%d", &matrix[i])
for j := range matrix[i] {
fmt.Scanf("%d", &matrix[i][j])
}
}
fmt.Println(matrix)
return matrix
}
func main() {
var (
n, m int
)
fmt.Println("Number of lines : ")
fmt.Scan(&n)
fmt.Println("Number of columns: ")
fmt.Scan(&m)
makeMatrix(n, m)
}
i'm trying to write a function that creates a matrix where the user can input the dimensions of the matrix as well as the values in it. I managed to get a result but i notice that when it comes to inputting the values the function ignores one of every two indexes and fills it with 0. I'm wracking my head but it doesn't make sense to me...
package main
import "fmt"
func makeMatrix(n int, m int) [][]int {
matrix := make([][]int, n)
for i := range matrix {
matrix[i] = make([]int, m)
}
fmt.Println("Enter elements : ")
for i := range matrix {
fmt.Scanf("%d", &matrix[i])
for j := range matrix[i] {
fmt.Scanf("%d", &matrix[i][j])
}
}
fmt.Println(matrix)
return matrix
}
func main() {
var (
n, m int
)
fmt.Println("Number of lines : ")
fmt.Scan(&n)
fmt.Println("Number of columns: ")
fmt.Scan(&m)
makeMatrix(n, m)
}
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删除此行＆amp;它应该按照您的预期工作。
fmt.scanf（“％d”，＆amp; matrix [i]）您已经在
matrix [i] [j] [j]上进行scanf，它将读取<<<代码> i ＆amp;j的每次迭代 - 您无需在matrix [i]上读取/scanf。Remove this line & it should work as you expected.
fmt.Scanf("%d", &matrix[i])You are already doing Scanf on
matrix[i][j]which will read each iteration ofi& each iteration ofj- you don't need to read/Scanf onmatrix[i].