端口类型和由stunclient返回的对称类型之间的关系是什么？
运行电击命令您可以看到返回的描述将指示端口是保存端口还是随机端口，并且B0也将指示它是否是保留端口或随机端口。 B3是对NAT类型是否对称的描述？ 据我了解，所有圆锥形类型的NAT均为保存端口，所有对称类型均为随机端口。这不是重复的描述吗？
有人可以告诉我这两者到底有什么区别？
Running the stun command you can see that the description returned will indicate whether the port is a preserves port or a random port and that b0 will also indicate whether it is a preserves port or a random port.
And b3 is a description of whether the NAT type is symmetric or not symmetric?
As I understand it, all Cone type NATs are preserves port and all symmetric type ones are random port. Isn't this a duplicate description?
Can someone tell me what exactly is the difference between these two?
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对称类型具有许多不同的算法，它取决于内核代码，并且总是显示随机或增加之类的算法，您可以看到您的OS'内核代码以深入理解。
Symmetric type has many different algorithms as for realising, it depends on the kernel code, and it always shows like random or increase, you can see your OS' kernel code for deep understand.