如何使Awt在单击的矩形上绘制网格？

Question

我是制作TIC TAC脚趾游戏的学生，目前拥有大部分UI和网格本身。我知道AWT没有数据，并且挥杆更有用和有用，但是我正在被教导，并且在AWT上拥有最多的资源。我目前有5个类：

GUI类：

import java.awt.*;
import javax.swing.JFrame;

public class GUI{
    JFrame frame1;
    Board board1;
    Buttons buttons;
    MyMenu menu1;

    public GUI() {
        frame1 = new JFrame("Tic Tac Toe");
        board1 = new Board(3,3 ,200);
        buttons = new Buttons(this);
        menu1 = new MyMenu(this);
    }

    public void start () {
        frame1.setLayout(new FlowLayout());
        board1.setBackground(Color.BLACK);
        frame1.setMenuBar(menu1);
        frame1.add(board1);
        frame1.add(buttons);
        frame1.pack();
        frame1.setVisible(true);
    }
    
    public static void main (String[] args) {
        GUI gui = new GUI();
        gui.start();
    }
    
    public void setBackground (Color c) {
        board1.setBackground(c);
    }
    
    public void closeGame() {
        frame1.dispose();
    }
}

董事会类：

import java.awt.Canvas;
import java.awt.Graphics;
import java.awt.Color;
import java.awt.*;

public class Board extends Canvas {
    Cell[][] array;
    int rows, cols;
    public Board(int rows, int cols, int size) {
        this.rows = rows;
        this.cols = cols;
        array = new Cell[rows][cols];
        for (int r = 0; r < rows; r++) {
            int y = r * size;
            for (int c = 0; c < cols; c++) {
                int x = c * size;
                array[r][c] = new Cell(x, y, size);
            }   
        }
        setSize(cols*size,rows*size);
    }
    
    public int getNumRows() {
        return rows;
    }
    
    public int getNumCols () {
        return cols;
    }

    public void draw(Graphics g) {
        for (Cell[] row : array) {
            for (Cell cell : row) {
                cell.paint(g);
            }
        }
    }

    public void paint(Graphics g) {
        draw(g);
    }
}

单元类：

import java.awt.Color;
import java.awt.*;

public class Cell
{
    private final int x;
    private final int y;
    private final int size;
    int rows;
    int cols;
    Cell[][] array = new Cell[rows][cols];
    public Cell(int x, int y, int size) {
        this.x = x;
        this.y = y;
        this.size = size;
    }

    public void fillArray() {
        for (int r = 0; r < rows; r++) {
            int y = r * size;
            for (int c = 0; c < cols; c++) {
                int x = c * size;
                array[r][c] = new Cell(x, y, size);
            }
        }
    }

    public void paint(Graphics g) {
        g.setColor(Color.YELLOW);
        g.drawRect(x, y, size, size);
    }
}

按钮类：

import java.awt.*;
import java.awt.event.*;

public class Buttons extends Panel implements ActionListener {
    Button test;
    Button giveIn;
    GUI gui;

    public Buttons(GUI gui) {
        this.gui = gui;
        giveIn = new Button("GIVE UP!");
        this.add(giveIn);
        giveIn.addActionListener(this);

    }
    public void actionPerformed(ActionEvent e) {
        if (e.getSource()== giveIn) {
            gui.closeGame();
        }
    }
}

我还有另一个类，实现了菜单，但没有觉得有必要包括。我将如何实施和如何实施它，因此当我在网格上单击矩形时，将某物涂在特定的矩形上？我知道我需要一个鼠标侦听器，以及在我的油漆方法上进行某种语句，以及一些返回单元格或矩形单击的方法。这样的事情如何实现？