仅更改第七栏的颜色 - （特定的蜡烛颜色交易图）

发布于 2025-01-21 20:57:19 字数 321 浏览 3 评论 0原文

我想改变一支蜡烛的颜色。例如，仅第七。

我尝试了barcolor和偏移量，但它也指出了以前的所有7个，您能帮我一个黄色的第7个吧吗？

 //@version=5
indicator('Previous Candle High and Low', shorttitle='Prev. H/L', overlay=true)
dt = time - time[1]
patternLabelPosHigh = close[7]


barcolor(color=bar_index ? color.yellow : na, offset=-6)

谢谢！

原文

I would like to change the color of a single candle. For example only the 7th.

I tried with barcolor and offset but it also points out all the previous ones of 7, Can you help me to get only the 7th bar in yellow ?

 //@version=5
indicator('Previous Candle High and Low', shorttitle='Prev. H/L', overlay=true)
dt = time - time[1]
patternLabelPosHigh = close[7]


barcolor(color=bar_index ? color.yellow : na, offset=-6)

Thank you !

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铃予 2025-01-28 20:57:19

如果您想追溯仅绘制左侧的第七栏并重新绘制结果，则必须检查当前条的状态。

下面的结构看起来多余，但是就我测试而言，它涵盖了所有可能的市场状态，下面的脚本将不断向左画7个bar，并在每个新栏上重新绘制：

//@version=5
indicator("Past barcolor()")
pastBar = input.int(7, title = "Past Bar", minval = 1)     
barcolor((barstate.islast or barstate.isrealtime) and (not barstate.isconfirmed or barstate.islastconfirmedhistory) ? color.new(color.blue, 0) : na, offset = - pastBar)

If you would like to retroactively paint only the 7th bar to the left and redraw the results, you have to check the current bar's state.

The construction below looks redundant, however it covers all possible states of the market as far as I tested, the script below will constantly paint 7th bar to the left and redraw on every new bar:

//@version=5
indicator("Past barcolor()")
pastBar = input.int(7, title = "Past Bar", minval = 1)     
barcolor((barstate.islast or barstate.isrealtime) and (not barstate.isconfirmed or barstate.islastconfirmedhistory) ? color.new(color.blue, 0) : na, offset = - pastBar)