python格式化整数

发布于 2025-01-21 19:54:30 字数 411 浏览 2 评论 0原文

这是我从BMD Hyperdeck中获得的请求，它包含SD卡上的视频文件和视频的长度。我需要每个文件的长度，在我的代码列表中分开。这样的方法是什么？

b'206 disk list:\r\nslot id: 1\r\n1: Timecode.mp4 H.264 1080p25 00:01:00:00\r\n2: Video_1.mp4 H.264 1080p25 00:00:09:07\r\n3: Video_2.mp4 H.264 1080p25 00:00:07:04\r\n4: Video_3.mp4 H.264 1080p25 00:00:10:19\r\n5: Video_4.mp4 H.264 1080p25 00:00:04:16\r\n6: Video_5.mp4 H.264 1080p25 00:00:05:21\r\n\r\n'

原文

This is the Request I get from an BMD Hyperdeck, it contains the Video-files on the SD-Cards an the lengths of the Videos. I need the lengths of every file, separate in a List for my Code. What would be the right way to something like this?

b'206 disk list:\r\nslot id: 1\r\n1: Timecode.mp4 H.264 1080p25 00:01:00:00\r\n2: Video_1.mp4 H.264 1080p25 00:00:09:07\r\n3: Video_2.mp4 H.264 1080p25 00:00:07:04\r\n4: Video_3.mp4 H.264 1080p25 00:00:10:19\r\n5: Video_4.mp4 H.264 1080p25 00:00:04:16\r\n6: Video_5.mp4 H.264 1080p25 00:00:05:21\r\n\r\n'

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沫离伤花 2025-01-28 19:54:30

这可以使用正则表达式和Findall来实现：

import re

a = b"206 disk list:\r\nslot id: 1\r\n1: Timecode.mp4 H.264 1080p25 00:01:00:00\r\n2: Video_1.mp4 H.264 1080p25 00:00:09:07\r\n3: Video_2.mp4 H.264 1080p25 00:00:07:04\r\n4: Video_3.mp4 H.264 1080p25 00:00:10:19\r\n5: Video_4.mp4 H.264 1080p25 00:00:04:16\r\n6: Video_5.mp4 H.264 1080p25 00:00:05:21\r\n\r\n"
str_a = str(a)
length = re.findall(r"[0-9]{2}:[0-9]{2}:[0-9]{2}:[0:9]{2}", str_a)
print(length)

This can be achieved using the regular expressions and findall:

import re

a = b"206 disk list:\r\nslot id: 1\r\n1: Timecode.mp4 H.264 1080p25 00:01:00:00\r\n2: Video_1.mp4 H.264 1080p25 00:00:09:07\r\n3: Video_2.mp4 H.264 1080p25 00:00:07:04\r\n4: Video_3.mp4 H.264 1080p25 00:00:10:19\r\n5: Video_4.mp4 H.264 1080p25 00:00:04:16\r\n6: Video_5.mp4 H.264 1080p25 00:00:05:21\r\n\r\n"
str_a = str(a)
length = re.findall(r"[0-9]{2}:[0-9]{2}:[0-9]{2}:[0:9]{2}", str_a)
print(length)

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