如何从Instagrapi列表响应中获取某些数据

Question

因此，我正在研究一些代码，以拉出喜欢Instagram上帖子的人的照片。我正在为API系统使用Instagrapi，但是使用api.media_likers返回所需信息列表。由于某些原因，它将其返回typeError：'userShort'对象无法订阅。我不确定该怎么做，因为这里的代码：

from instagrapi import Client


insta_user = ""
insta_pass = ""

api = Client() #logs in
api.login(insta_user, insta_pass) #logs in

url = input("Please enter the url to the populer photo: ")
populer_photo_id = api.media_pk_from_url(url)   # gets media id from url given from user
print(f"got media id ==> {populer_photo_id}")

get_likes = api.media_info(populer_photo_id).dict() # gets number of likes
likes = get_likes['like_count']                     # gets number of likes


likers_res = api.media_likers(populer_photo_id) # gets the people who have liked said post (returns in list)


print(list((object['username'] for object in likers_res)))

应该从列表中返回用户名，而是返回

Please enter the url to the populer photo: https://www.instagram.com/p/xxxxxxxxxx/
got media id ==> xxxxxxxxxxxxxxxx
Traceback (most recent call last):
  File "c:\Users\gagem\Documents\Pr0j3cts\insta-promo\testing-api-file.py", line 43, in <module>
    print(list((object['username'] for object in likers_res)))
  File "c:\Users\gagem\Documents\Pr0j3cts\insta-promo\testing-api-file.py", line 43, in <genexpr>
    print(list((object['username'] for object in likers_res)))
TypeError: 'UserShort' object is not subscriptable

Answer 1

您只需要更改

print(list((object['username'] for object in likers_res)))

为

print(list((object.username for object in likers_res)))