每当我按下键时，我如何才能将其递增和打印，而不仅仅是一次？

发布于 2025-01-21 18:09:31 字数 369 浏览 0 评论 0原文

使用以下程序，每当我按“ A”键时，键>变量 1 。问题是，如果我不立即放任键，键>键>变量将继续通过1递增。

每当我按键以忽略保留方面时，我如何才能将其递增（和打印）？

import keyboard
keypresses = 0
while True:
    if keyboard.is_pressed("a"):
        keypresses = keypresses +1
        print(keypresses)   
        print("A Key Pressed")
        break

原文

With the below program, whenever I press the "a" key, the keypresses variable increments by 1. The problem is, if I don't immediately let go fo the key, the keypresses variable continues to increment by 1.

How can I get it to increment (and print) whenever I press the key, ignoring the hold aspect?

import keyboard
keypresses = 0
while True:
    if keyboard.is_pressed("a"):
        keypresses = keypresses +1
        print(keypresses)   
        print("A Key Pressed")
        break

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

み格子的夏天 2025-01-28 18:09:31

我了解您想要它，以便仅一旦（不是无限期）按下打印，并且只要a键再次释放并再次按下，它就会再次打印。

定义一个变量，按，以获取是否仍在按下或发布键：

import keyboard

keypresses = 0
pressing = False

while True:
    if keyboard.is_pressed("a"):
        if not pressing:
            pressing = True
            keypresses = keypresses +1
            print(keypresses)   
            print("A Key Pressed")
    else:
        pressing = False

I understand that you want it so that pressing and holding only prints once (not indefinitely), and it will print again as long as the a key is released and pressed again.

Define a variable, pressing, to get if the key is still being pressed, or released:

import keyboard

keypresses = 0
pressing = False

while True:
    if keyboard.is_pressed("a"):
        if not pressing:
            pressing = True
            keypresses = keypresses +1
            print(keypresses)   
            print("A Key Pressed")
    else:
        pressing = False

回复收藏 0 原文

聽兲甴掵 2025-01-28 18:09:31

如果您删除这样的休息语句：

import keyboard
keypresses = 0
while True:
    if keyboard.is_pressed("a"):
        keypresses = keypresses +1
        print(keypresses)   
        print("A Key Pressed")
    break

这是不起作用的，并且运行它时，它会立即完成。
因为键盘.is_pressed仅检测现在
正是由于此事，

如果您在Windows中，这会导致CPU太多，您可以将msvcrt代替：-)

if you remove the break statement like this:

import keyboard
keypresses = 0
while True:
    if keyboard.is_pressed("a"):
        keypresses = keypresses +1
        print(keypresses)   
        print("A Key Pressed")
    break

this does not work, and when you run it, it is instantly finished the while cycle.
because the keyboard.is_pressed only detect now
and precisely because of this, which caused too many cpu

if you are in windows , you can use msvcrt to instead :-)

回复收藏 0 原文

裂开嘴轻声笑有多痛 2025-01-28 18:09:31

我将删除break语句。
在 python docs 在/循环时，将最内向的退出，在您的情况下，该循环将是

while True:

I'd remove the break statement.
On the Python docs you can see that break exits the innermost for/while loop, in your case the that loop would be the