在C＃中发送MIDI SYSEX消息

发布于 2025-01-21 16:59:11 字数 303 浏览 0 评论 0原文

我正在尝试弄清楚如何在单击按钮时发送一个简单的Winform应用，该应用程序发送SYSEX MIDI消息，所以按钮1发送： -

F0 7F 22 02 50 01 31 00 31 00 31 F7

按钮2发送：

F0 7F 22 02 50 01 32 00 31 00 31 F7

依此类推...

我能够找到很多信息关于发送笔记和仪器数据，但与Sysex并不是什么。我玩过Sanford参考文献，这似乎使我更加接近，但对Sysex的用法仍然没有。

原文

I'm trying to figure out how to make a simple Winform app that sends a SysEx MIDI message when I click a button, so button 1 sends:-

F0 7F 22 02 50 01 31 00 31 00 31 F7

Button 2 sends:

F0 7F 22 02 50 01 32 00 31 00 31 F7

and so on...

I was able to find lots of info about sending notes and instrument data but nothing really about sysex. I have played with the Sanford reference which seemed to get me closer but still nothing about Sysex usage.

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星光不落少年眉 2025-01-28 16:59:11

有各种MIDI库可用，大多数以一种或另一种形式支持SYSEX。我主要使用 管理> manded-midi 尽管我' VE之前使用了Sanford套餐。

至少在托管中间中，发送SYSEX消息与获取imidioutput（通常来自MidiaCcessManager）一样简单，然后调用send> send方法。例如：

// You'd do this part just once, of course...
var accessManager = MidiAccessManager.Default;
var portId = access.Outputs.First().Id;
var port = await access.OpenOutputAsync(portId);

// You'd port this part in your button click handler.
// The data is copied from the question, so I'm assuming it's okay...
var message = new byte[] {
    0xF0, 0x7F, 0x22, 0x02, 0x50, 0x01,
    0x31, 0x00, 0x31, 0x00, 0x31, 0xF7 };

port.Send(message, 0, message.Length, timestamp: 0);

There are various MIDI libraries available, and most support SysEx in one form or another. I've mostly used the managed-midi package although I've used the Sanford package before.

In managed-midi at least, sending a SysEx message is as simple as obtaining an IMidiOutput (usually from a MidiAccessManager) and then calling the Send method. For example:

// You'd do this part just once, of course...
var accessManager = MidiAccessManager.Default;
var portId = access.Outputs.First().Id;
var port = await access.OpenOutputAsync(portId);

// You'd port this part in your button click handler.
// The data is copied from the question, so I'm assuming it's okay...
var message = new byte[] {
    0xF0, 0x7F, 0x22, 0x02, 0x50, 0x01,
    0x31, 0x00, 0x31, 0x00, 0x31, 0xF7 };

port.Send(message, 0, message.Length, timestamp: 0);

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