HasmanyThrough查询没有Laravel_Through_key

Question

有了Laravel Hasmanythough的关系，我如何防止添加额外的密钥？有没有pivot或simiar的？

我正在尝试执行联盟加入，并且需要将列保持相同。

SQLSTATE [21000]：违反基数：1222使用的选择语句有不同数量的列，

SELECT
    count(*) AS aggregate
FROM ((
        SELECT
            `order_payments`.`id`,
            `order_payments`.*,
            `orders`.`user_id` AS `laravel_through_key`
        FROM
            `order_payments`
            INNER JOIN `orders` ON `orders`.`id` = `order_payments`.`order_id`
        WHERE
            `orders`.`user_id` = 1)
    UNION (
        SELECT
            `orders`.`id`
        FROM
            `orders`
        WHERE
            `orders`.`user_id` = 1
            AND `orders`.`user_id` IS NOT NULL)) AS `temp_table`

我无法使用Make -Make -Hidden，如另一个问题所建议的，

$payments = auth()->user()->orderPayments()->select('order_payments.id');

$orders = auth()->user()->orders()->select('orders.id');

$payments->union($orders)->paginate(50);

我想我可以在不手动的情况下做到这一点，但只是想知道还有另一种方法吗？

class User extends Authenticatable implements UserContract {
    /**
     * Orders for this User
     */
    public function orders()
    {
        return $this->hasMany(Order::class);
    }

    /**
     * Order Payments for this User
     */
    public function orderPayments()
    {
        return $this->hasManyThrough(OrderPayment::class, Order::class);
    }
}