flutter的firebase动态链接在创建链接时会自动删除自定义Queryparameters

Question

大家好，我在从Firebase Dynamic Link和Flutter中获取参数很难。即使在创建链接时提供值时，它也不会以某种方式显示在动态链接中。谁能帮我解决这个问题？在过去的两天里，我没有任何帮助。

这是代码。

class DynamicLinkService {
  String? _linkMessage;

  Future<String?> createDynamicLink(bool short, String? slug) async {
    final dynamicLinkParams = DynamicLinkParameters(
      link: Uri.parse("https://xyz.page.link/"),
      uriPrefix: "https://xyz.page.link/product?prdt=$slug",
      androidParameters: AndroidParameters(
        packageName: "com.example.example",
        minimumVersion: 24,
      ),
      iosParameters: IosParameters(
        bundleId: "com.example.iosexample",
        appStoreId: "13719873",
        minimumVersion: "1.0.1",
      ),
    );

    Uri? url;

    if (short) {
      // final dynamicLink =
      // await FirebaseDynamicLinks.instance.buildShortLink(dynamicLinkParams);
      final dynamicLink = await dynamicLinkParams.buildShortLink();
      url = dynamicLink.shortUrl;
    } else {
      final dynamicLink = await dynamicLinkParams.buildUrl();
      // await FirebaseDynamicLinks.instance.buildLink(dynamicLinkParams);
      url = dynamicLink;
    }

    _linkMessage = url.toString();
    return _linkMessage;
  }

  Future<void> initDynamicLink(BuildContext context) async {

    FirebaseDynamicLinks.instance.onLink(
      onSuccess: (dynamicLink) async {
       final Uri? deepLink = dynamicLink?.link;
       var isProduct = deepLink?.pathSegments.contains('product');
       if (isProduct == true) {
         String? slug = deepLink?.queryParameters['prdt'];
         print("2Li $slug");

         if (deepLink != null) {
           if (slug != null || slug != "") {
             context.read<ProductController>().saveSlug(slug!).whenComplete(() {
               Navigator.of(context).pushNamed("/ProductDetail");
             });
           }
         } else {
           return null;
         }
       } else {
         return null;
       }
      }
    );

    final PendingDynamicLinkData? data =
      await FirebaseDynamicLinks.instance.getInitialLink();
    try {
      final Uri? deepLink = data?.link;
      print("1111111, $deepLink");
      var isProduct = deepLink?.pathSegments.contains('product');
      if (isProduct == true) {
        String? slug = deepLink?.queryParameters['prdt'];
        print("2Li $slug");

        if (deepLink != null) {
          if (slug != null || slug != "") {
            context.read<ProductController>().saveSlug(slug!).whenComplete(() {
              Navigator.of(context).pushNamed("/ProductDetail");
            });
          }
        } else {
          return null;
        }
      } else {
        return null;
      }

    } catch(e) {
      print("No DeepLink Found");
    }

  }
}

这是正在创建的URL，

https://xyz.page.link/product?amv=24&apn=com.example.example&ibi=com.example.example&imv=1.0.1&isi=1613285148&link=https%3A%2F%2Fxyz.page.link%2F

我尝试了几种方法，但找不到获得Queryparams的方法。

帮助您将不胜感激。

谢谢。

Answer 1

查询参数应在链接中（目标应用程序将打开的链接），而不是uriprefix（应用程序的域URI前缀）：

link: Uri.parse("https://xyz.page.link/product?prdt=$slug"),
uriPrefix:"https://xyz.page.link",