如何制作一系列指针并使用户输入其大小？
我想制作一个数组，在此数组内有这样的指针： int *arrp [size];，我希望用户输入它的大小。 我试图这样做：
#include <iostream>
using namespace std;
int main ()
{
int size;
cout << "Enter the size of the array of pointers" << endl;
cin >> size;
int *arrp[size];
return 0;
}
但这无效。 我还试图这样做：
#include <iostream>
using namespace std;
int main ()
{
int size;
cout << "Enter the size of the array of pointers" << endl;
cin >> size;
int* arrp[] = new int[size];
return 0;
}
也不起作用，有人可以帮忙吗？
第一个代码的错误是大小必须是恒定的，我试图通过编写第二个代码来修复这一点，但在第9行中给出了“ new”一词的错误： E0520的初始化，'{...}'预期的聚合对象 以及同一行中大小的另一个错误： C2440“初始化”：无法从'int *'转换为'int *[]'
I want to make an array, and inside this array there are pointers, like this:int *arrp[size]; and I want the user to enter the size of it.
I tried to do this:
#include <iostream>
using namespace std;
int main ()
{
int size;
cout << "Enter the size of the array of pointers" << endl;
cin >> size;
int *arrp[size];
return 0;
}
but this doesn't work.
I also tried to do this:
#include <iostream>
using namespace std;
int main ()
{
int size;
cout << "Enter the size of the array of pointers" << endl;
cin >> size;
int* arrp[] = new int[size];
return 0;
}
also doesn't work, can someone help?
The error of the first code is that the size must be constant, I tried to fix that by writing the 2nd code but it gives an error for the word "new" in line 9:
E0520 initialization with '{...}' expected for aggregate object
and another error for the size in the same line:
C2440 'initializing': cannot convert from 'int *' to 'int *[]'
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要制作一系列指针，您应该输入：
int ** arr = new Int*[size]我们键入2星'*'，第一个是指通向整数的指针，第二个指指向整数指针的指针，然后我们通过键入
= new Int*来在这些指针的内存中占有一席之地。 [size]，您可以将其用作存储在堆中的2D数组（而不是堆栈），请访问此网站以了解差异： https://www.geeksforgeeks.org/stack-vs-vs-heap-memory-allocation/ 。要了解如何使用一系列指针来指向整数指针，您可以看到此视频： https://www.youtube.com/watch?v=gnguma_ur0u&ab_channel=thecherno 。
To make an array of pointers you should type:
int** arr = new int*[size]we type 2 stars '*', the first mean a pointer to an integer, the second means a pointer to the pointer to the integer, and then we make a place in the memory for those pointers by typing
= new int*[size], you can use this as a 2D array that stored in the heap (not the stack) go to this website to know the difference: https://www.geeksforgeeks.org/stack-vs-heap-memory-allocation/.to know more about how to use an array of pointers to a pointer to an integers you can see this video: https://www.youtube.com/watch?v=gNgUMA_Ur0U&ab_channel=TheCherno.