如何找到多个事件的两个时间之间的持续时间？

发布于 2025-01-21 09:41:14 字数 727 浏览 1 评论 0原文

我的任务是找出为总线充电的时间，而充电类型= 1时，这意味着充电器已插入。我如何找到此持续时间？另外，我需要找出充电频率，有什么方法也可以做到吗？

这是当前的代码：

#Duration loop
foundEnd = False

for i in range(len(dfDur01Mar22)):
    #only display bus 'SG3079S'
    if dfDur01Mar22.iloc[i,1] == 'SG3079S':
        #print 'end' when first '0' appears
        if not foundEnd and dfDur01Mar22.iloc[i,2] == 0:
            print('end')
            foundEnd = True
        #if charging type is 1
        elif dfDur01Mar22.iloc[i,2] == 1:
            print(dfDur01Mar22.iloc[i,0],dfDur01Mar22.iloc[i,1],dfDur01Mar22.iloc[i,2])
            foundEnd = False

这是从中的输出：在此处输入图像描述

原文

My task is to find out how long the bus is charged for, and when charging type = 1, it means that the charger is plugged in. How do i find the duration from this? Also i need to find out the charging frequency, is there a way i can do that too?

Here is the code currently:

#Duration loop
foundEnd = False

for i in range(len(dfDur01Mar22)):
    #only display bus 'SG3079S'
    if dfDur01Mar22.iloc[i,1] == 'SG3079S':
        #print 'end' when first '0' appears
        if not foundEnd and dfDur01Mar22.iloc[i,2] == 0:
            print('end')
            foundEnd = True
        #if charging type is 1
        elif dfDur01Mar22.iloc[i,2] == 1:
            print(dfDur01Mar22.iloc[i,0],dfDur01Mar22.iloc[i,1],dfDur01Mar22.iloc[i,2])
            foundEnd = False

and here is the output from it :
enter image description here

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征﹌骨岁月お 2025-01-28 09:41:14

您可以使用DateTime模块来找出2个事件之间的时间：

from datetime import datetime

start = datetime.now()
#Func here
end = datetime.now()

total = end - start

seconds_elapsed = total.total_seconds()

print (seconds_elapsed)

You can use the datetime module to figure out the amount of time between 2 events:

from datetime import datetime

start = datetime.now()
#Func here
end = datetime.now()

total = end - start

seconds_elapsed = total.total_seconds()

print (seconds_elapsed)

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