验证场结构的正则表达

发布于 2025-01-21 09:23:03 字数 193 浏览 5 评论 0原文

我想在Linux中实现一个正则表达式，该表达式使用GREP允许我验证一个字段包含15个数值，并且占据第五位置的值（从左开始）是5或6。

我已经达到了点但是，确定其最多包含15个值的要求，我找不到占据第五位置的一个值是5或6。这是：

grep -E "^[0-9]{1,15}"

有什么想法吗？

原文

I would like to implement a regular expression in linux that using grep allows me to verify that a field contains 15 numerical values and that the value occupying the fifth position (starting from left) is either a 5 or a 6.

I have reached the point of defining the requirement that it contains a maximum of 15 values, however, I can not get that the one that occupies the fifth position is a 5 or 6. It would be:

grep -E "^[0-9]{1,15}"

Any idea?

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彻夜缠绵 2025-01-28 09:23:03

对于正好的15个数字，5个位置为5或6：

grep -E "^[0-9]{4}[56][0-9]{10}$"

^ String的启动
[0-9] {4}匹配4位数字
[56]匹配5或6
[0-9] {10}匹配10位数字
$结束of string

To match at least the first 5 characters followed by 0-10 digits after it, and allow a partial match like matching 123462222233333 in 12346222223333344444

grep -Eo "^[0-9]{4}[56][0-9]{0,10}"

For exactly 15 numbers, and the 5 position is either 5 or 6:

grep -E "^[0-9]{4}[56][0-9]{10}quot;

^ Start of string
[0-9]{4} Match 4 digits
[56] Match either 5 or 6
[0-9]{10} Match 10 digits
$ End of string

To match at least the first 5 characters followed by 0-10 digits after it, and allow a partial match like matching 123462222233333 in 12346222223333344444