Django管理面板HealthCheck

发布于 2025-01-21 08:26:29 字数 131 浏览 2 评论 0原文

我想为我的Django管理面板创建一个HealthCheck端点。 我想通过admin.site.register_view进行注册软件包),但我不知道如何使公众可以访问它,而无需先验证。

有什么想法吗?

I want to create a healthcheck endpoint for my django admin panel.
I want to register it via admin.site.register_view (I am using the adminplus package) but I can't figure out how to made it accessible to the public, without the need to authenticate first.

Any ideas?

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堇年纸鸢 2025-01-28 08:26:29

因此,我最终在adminplusmixin的子类中结束了def has_permission(self,request)

from adminplus.sites import AdminPlusMixin


class MyAdmin(AdminPlusMixin, AdminSite):

    def has_permission(self, request):
        if request.resolver_match.url_name == 'admin-healthcheck':
            return True
        return super().has_permission(request)

So I ended up overriding def has_permission(self, request) in subclass of AdminPlusMixin:

from adminplus.sites import AdminPlusMixin


class MyAdmin(AdminPlusMixin, AdminSite):

    def has_permission(self, request):
        if request.resolver_match.url_name == 'admin-healthcheck':
            return True
        return super().has_permission(request)
偷得浮生 2025-01-28 08:26:29

我相信软件包已经过时了,相反,您可以做以下操作:

models.py 中创建一个代理模型,例如:

class Proxy(models.Model):

    id = models.BigAutoField(db_column='id', primary_key=True)

    def str(self):
        return "<Label: id: %d>" % self.id

    class Meta:
        managed = False
        verbose_name_plural = 'proxies'
        db_table = 'proxy'
        ordering = ('id',)

它只是一个 mysql视图,即创建的从AM现有表

 create view proxy
    as select id
    from samples
    LIMIT 10;

,最后在 admin.py

@admin.register(Proxy)
class LabelAdmin(admin.ModelAdmin):
    change_list_template = 'label_view.html'
    def changelist_view(self, request, extra_context=None):
      ...
        return render(request, "label_view.html", context)

,以此方式显示在您正在使用的应用程序中。

您所拥有的是您的视图中的函数。

I believe that package is outdated, instead you could do something like the following:

Created a proxy model in models.py such as:

class Proxy(models.Model):

    id = models.BigAutoField(db_column='id', primary_key=True)

    def str(self):
        return "<Label: id: %d>" % self.id

    class Meta:
        managed = False
        verbose_name_plural = 'proxies'
        db_table = 'proxy'
        ordering = ('id',)

Which is just a mysql view that a created from am existing table

 create view proxy
    as select id
    from samples
    LIMIT 10;

And finally in admin.py

@admin.register(Proxy)
class LabelAdmin(admin.ModelAdmin):
    change_list_template = 'label_view.html'
    def changelist_view(self, request, extra_context=None):
      ...
        return render(request, "label_view.html", context)

This way it will show in the admin panel, inside the app you're working on.

Probably what you have is a function in your views.py, in this case you should replace that function content where the "..." are in the LabelAdmin class.

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