C＆＃x2B;＆＃x2B;模板类型包装元组专业

发布于 2025-01-21 03:41:17 字数 531 浏览 3 评论 0原文

试图实现元组类型时，我会遇到一个空元组。
这是我使用的类型结构：

template <class T, class... Ts>
struct Tuple : public Tuple<Ts...> {};

template <class T>
struct Tuple {};

一旦我尝试添加一个无类型编译器的过载，编译器就会抱怨：类模板'tuple''的模板参数太少：

template <> struct Tuple<> {};

我想是因为这是因为首先以至少一种提供的类型声明了元组类型，并且编译器无法用不同的模板参数超载相同的类型，但是我想知道我如何在不完全重组我的代码的情况下解决此问题。

我的第一个想法是定义元组，例如template＆lt; class ... ts＆gt;结构元组{};首先，而不是添加其他过载，但是编译器比向大量模板参数投诉。

原文

When trying to implement a tuple type i run into the problem an empty tuple.
This is the type structure i used:

template <class T, class... Ts>
struct Tuple : public Tuple<Ts...> {};

template <class T>
struct Tuple {};

As soon as i try to add an overload for no type the compiler complains: Too few template arguments for class template 'Tuple':

template <> struct Tuple<> {};

I guess it's because the Tuple type was declared with at least one provided type at first and the compiler can't overload the same type with a different set of template parameters, but i wonder how i could solve this problem without completely restructuring my code.
My first idea was to define the tuple like template <class... Ts> struct Tuple {}; first and than add the other overloads, but the compiler than complains for to much template arguments.

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七禾 2025-01-28 03:41:17

您的模板期望至少一个参数。您可以这样更改它以允许零或更多：

template <typename ... Ts>
struct Tuple;

template <>
struct Tuple<> {};

template <class T,class... Ts>
struct Tuple<T,Ts...> : public Tuple<Ts...> {};

int main()
{
    Tuple<int,int,double> t;
}

Your template expects at least one parameter. You can change it like this to allow zero or more:

template <typename ... Ts>
struct Tuple;

template <>
struct Tuple<> {};

template <class T,class... Ts>
struct Tuple<T,Ts...> : public Tuple<Ts...> {};

int main()
{
    Tuple<int,int,double> t;
}

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