如何使用SED使用字符串作为搜索参数提取字符串
我试图返回一个通过输出不断变化的字符串。 我认为 grep 和 sed 可能是处理这个问题的最佳方法。 基本上，输出呈现一个大的文本字段，其中包含一些内容，目标
https://rancher.website.com/version1/proj/abcd123?somethingsomethingsomethingetc
是返回第一个实例，
https://rancher.website.com/version1/proj/
因为有多个实例，然后返回 abcd123 的内容，直到 ? 符号之前。
我一直在尝试调整 sed 命令，但我的语法不断出错，而且我很难理解到目前为止给出的解释。我认为我的问题之一可能是因为 sed “搜索”缺乏更好的术语，是针对字符串而不是单个字符运行的。另外，正斜杠也是一个问题，因为我认为它们在 sed 命令中被解释为运算符？
我尝试使用的命令或多或少是：
grep 'https://rancher.website.com/version1/projects/' grep.txt | sed 's/^.*'https:\/\/rancher.website.com\/version1\/projects\/'//g'
grep.txt 是初始命令的输出文本的容器
I am trying to return a string that is constantly changing via the output.
I decided grep and sed might be the best way to handle this.
Basically the output renders a large field of text that contains something to the effect of
https://rancher.website.com/version1/proj/abcd123?somethingsomethingsomethingetc
the goal is to return the FIRST instance of
https://rancher.website.com/version1/proj/
as there are multiple, and then return the contents of abcd123 up to the ? symbol before it.
I keep trying to tweak the sed command but keep running into errors with my syntax and I am having trouble wrapping my mind around the explanations given so far. I think one of my problems might be around the fact that the sed "search" for lack of a better term, is being run against a string rather than a single character. Also the forward slashes are a problem as I think those are being interpreted as operators in the sed command?
Command I am trying to use is more or less:
grep 'https://rancher.website.com/version1/projects/' grep.txt | sed 's/^.*'https:\/\/rancher.website.com\/version1\/projects\/'//g'
With grep.txt being the container for the output text of the initial command
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将最后一个
/之前的所有内容以及?中的所有内容替换为空字符串。当模式包含
/时，请使用不同的字符作为s分隔符以避免必须对其进行转义；我在上面使用了#。Replace everything up to the last
/and everything from?with empty strings.When the pattern includes
/, use a different character as thesdelimiter to avoid having to escape it; I've used#above.