python所有列表项目包含“ ./ && quot”;我想删除它
我正在使用python横向进入目录中的所有子文件夹 为了写入OS命令。我需要所有子文件夹的列表,但是列表正在以“ ./”为之前返回,我希望将此子字符串同时从所有列表中删除
我的脚本:到目前为止我的脚本:
import os
import glob
file_list = glob.glob("./*")
file_list.remove("./script.py")
print(file_list)
返回列表
['./folder1', './folder2', './folder3', './folder4', './folder5']
我想要
['folder1', 'folder2', 'folder3', 'folder4', 'folder5']
I am using python to transverse into all sub folders in a directory
and in order to write up the os commands. I need a list of all sub folders but the list is returning with the "./" ahead of the folder names and I am looking to remove this sub string from all list itmes simultaneously
My script so far:
import os
import glob
file_list = glob.glob("./*")
file_list.remove("./script.py")
print(file_list)
returns list
['./folder1', './folder2', './folder3', './folder4', './folder5']
I would like
['folder1', 'folder2', 'folder3', 'folder4', 'folder5']
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这可以通过列表理解和 str.lstrip() 方法来完成。
返回:
['folder1', 'folder2', 'folder3', 'folder4', 'folder5']
This can be done with a list comprehension and the
str.lstrip()
method.returns:
['folder1', 'folder2', 'folder3', 'folder4', 'folder5']
我更喜欢使用
pathlib
模块来处理这类事情。例如,如果您只想获取目录名称,可以这样做:I prefer using the
pathlib
module for this kind of stuff. For example, if you want to get just directory names, you can do this: