如何在生锈中多次使用变量？

发布于 2025-01-20 15:23:28 字数 259 浏览 2 评论 0原文

我知道Rust中借贷和拥有的基本原则。但是，我找不到解决以下情况的方法：

fn create_user(full_name: String) -> User {
  User {
    field1: full_name,
    field2: full_name,
  }
}

如果我想在上面的示例中将几个字段引用给给定参数怎么办？使用“*”不能解决问题，也没有编译。

在询问之前，我真的没有找到这个问题的答案。

原文

I know about the basic principles of borrowing and owning in Rust.
However, I can't find a way to solve the following situation:

fn create_user(full_name: String) -> User {
  User {
    field1: full_name,
    field2: full_name,
  }
}

What if I would like to reference couple of fields in the example above to the given argument? Using of the "*" doesn't solve the problem and is not compiling.

I really did not find an answer to this question for a while before asking.

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鲜血染红嫁衣 2025-01-27 15:23:28

有一些选项，包括（可能不仅）：

如果t是clone

fn create_user(full_name: T) -> User where T: Clone {
  User {
    field1: full_name.clone(),
    field2: full_name.clone(),
  }
}

如果t不是clone> clone，您可以利用field2作为返回参考的方法：

struct User {
   field1: T
}

impl User {
    pub fn field2(&self) -> &T {
        &self.field1
    }
}

fn create_user(full_name: T) -> User {
  User {
    field1: full_name,
  }
}

There are a few options, including (and probably not only):

If T is Clone

fn create_user(full_name: T) -> User where T: Clone {
  User {
    field1: full_name.clone(),
    field2: full_name.clone(),
  }
}

if T is not Clone, you could leverage field2 as a method returning a reference:

struct User {
   field1: T
}

impl User {
    pub fn field2(&self) -> &T {
        &self.field1
    }
}

fn create_user(full_name: T) -> User {
  User {
    field1: full_name,
  }
}

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