python |添加图案1 22 333 4444 55555＆＃x200b; ....？

发布于 2025-01-20 13:55:40 字数 316 浏览 1 评论 0原文

我如何添加 1 22 333 4444 55555 ....？

i) 情况 1：n = 1，v = 1

ii) 情况 2：n= 2，v = 23 （注：23 是由 1 + 22 推导出来的）

def create_sequence():

   n = int(input('Enter the number till which you want the sequence:'))

   for i in range(1,n+1):

       print(str(i) * i)

   

create_sequence()

原文

How do i do addition of 1 22 333 4444 55555 ....?

i) case 1: n = 1, v = 1

ii) case 2: n= 2, v = 23 (Note: 23 is derived as 1 + 22)

def create_sequence():

   n = int(input('Enter the number till which you want the sequence:'))

   for i in range(1,n+1):

       print(str(i) * i)

   

create_sequence()

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淡水深流 2025-01-27 13:55:40

您会生成形式str（i）*i的一系列元素，然后将其投入整数，然后sum该序列。

def create_sequence(n):
    return sum(int(str(i)*i) for i in range(1, n+1))

create_sequence(int(input('Enter the number till which you want the sequence: ')))

You generate a sequence of elements of the form str(i)*i, which you cast into an integer, then sum that sequence.

def create_sequence(n):
    return sum(int(str(i)*i) for i in range(1, n+1))

create_sequence(int(input('Enter the number till which you want the sequence: ')))

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别再吹冷风 2025-01-27 13:55:40

利用循环，它们是你的朋友

def create_sequence():

   n = int(input('Enter the number till which you want the sequence:'))
   sum = 0
   for x in range(1, n+1):
       string = ""
       for i in range(1, x+1):
           string += str(x)
       sum += int(string)
   return sum
print(create_sequence())

Take advantage of loops, they are your friend

def create_sequence():

   n = int(input('Enter the number till which you want the sequence:'))
   sum = 0
   for x in range(1, n+1):
       string = ""
       for i in range(1, x+1):
           string += str(x)
       sum += int(string)
   return sum
print(create_sequence())

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