绘制多个updatemenus
在这篇帖子的基础上,我尝试创建两个updatemenus< R
plotly
中的 /code> 允许选择两个因素的每种可能的组合。
这是我到目前为止所做的:
library(plotly)
X <- data.frame(x = 1:6,
y = 1:6,
z = 1:6,
gender = rep(c("M", "F"), each = 3),
eyes = rep(c("B", "G"), 3))
gg <- ggplot(data = X, aes(x = x, y = y)) +
geom_point(aes(color = z, alpha = interaction(gender, eyes))) +
scale_alpha_manual(values = rep(1, 4))
ggplotly(gg) %>%
layout(
updatemenus = list(
list(y = 1,
buttons = list(
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE, TRUE, TRUE)), 0:3),
label = "F&M"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), c(0, 2)),
label = "F"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), c(1, 3)),
label = "M"))),
list(y = .8,
buttons = list(
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE, TRUE, TRUE)), 0:3),
label = "B&G"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), 0:1),
label = "B"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), 2:3),
label = "G")))
)
)
)
数据:
# x y z gender eyes
# 1 1 1 M B
# 2 2 2 M G
# 3 3 3 M B
# 4 4 4 F G
# 5 5 5 F B
# 6 6 6 F G
编辑
例如,如果选择 F
和 B
,我希望仅显示一个数据点,即 (5, 5)
。
Building on this post, I am trying to create two updatemenus
in R plotly
that would allow to select every possible combination of two factors.
This is what I have done so far:
library(plotly)
X <- data.frame(x = 1:6,
y = 1:6,
z = 1:6,
gender = rep(c("M", "F"), each = 3),
eyes = rep(c("B", "G"), 3))
gg <- ggplot(data = X, aes(x = x, y = y)) +
geom_point(aes(color = z, alpha = interaction(gender, eyes))) +
scale_alpha_manual(values = rep(1, 4))
ggplotly(gg) %>%
layout(
updatemenus = list(
list(y = 1,
buttons = list(
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE, TRUE, TRUE)), 0:3),
label = "F&M"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), c(0, 2)),
label = "F"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), c(1, 3)),
label = "M"))),
list(y = .8,
buttons = list(
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE, TRUE, TRUE)), 0:3),
label = "B&G"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), 0:1),
label = "B"),
list(method = "restyle",
args = list(list(visible = c(TRUE, TRUE)), 2:3),
label = "G")))
)
)
)
The data:
# x y z gender eyes
# 1 1 1 M B
# 2 2 2 M G
# 3 3 3 M B
# 4 4 4 F G
# 5 5 5 F B
# 6 6 6 F G
This is the output, which does not work at all:
Edit
For instance, if F
and B
are selected, I would expect only a single data point to be displayed, namely (5, 5)
.
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当您创建此
plotly
对象时,plotly
将其分为五个迹线。因此,当您想要使用可见性时,您需要解决这些跟踪中的每一个。如果您有任何疑问,请告诉我!我使用 gg1 找到了 5 条痕迹以及每条痕迹中的内容。您可以在源代码窗格或
plotly_json()
中查看gg1
。通常(并非总是!),您会在
gg1$x$data
处找到跟踪,其中gg1
是plotly
对象。有五处痕迹。对于每个
args
,每个跟踪都需要 T 或 F 来实现可见性。这是代码:
更新
从我们的评论来看,我不认为此时可以使用彼此交互的
updatemenus
样式按钮。When you created this
plotly
object,plotly
divided it into five traces. So when you wanted to use visibility, you needed to address each of these traces. If you have any questions, let me know!I used
gg1
to find five traces and what was in each of these traces. You could look atgg1
in the source pane orplotly_json()
.Typically (not always!), you'll find the traces at
gg1$x$data
wheregg1
is theplotly
object.There are five traces. For each
args
, each trace needs a T or F for visibility.Here's the code:
Update
From our comments, I do not believe that it's possible at this time to use
updatemenus
style buttons that interact with each other.