php如果在课堂外调用功能

发布于 2025-01-20 09:00:07 字数 520 浏览 2 评论 0原文

我正在为网络平台制作SDK，有一个客户端类需要cookie来授权，并且有一个从cookie获取身份验证令牌的函数。所以我的问题是：如何检查函数是否在类外被调用。我需要这个，因为我想用密码保护这个函数，并且如果类调用它，它就可以在没有密码的情况下工作。这是我的代码：

public function gettoken(?string password = ""): string{
    //check if it's called inside of class
    if (fromClass() == true){
       //code that gets token
    }
    //if it's called outside of class
    if ($password == $this->password){
       //code that gets token
    }
    return "Incorrect password";
}

原文

I'm making SDK for a web platform, there is a client class which requires cookie to authorize and there is a function that gets auth token from cookie. So my question is: how to check if function was called outside of class. I need this because i want to protect this function with password and make it so if class called it, it would work without a password.
Here is my code:

public function gettoken(?string password = ""): string{
    //check if it's called inside of class
    if (fromClass() == true){
       //code that gets token
    }
    //if it's called outside of class
    if ($password == $this->password){
       //code that gets token
    }
    return "Incorrect password";
}

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

莫言歌 2025-01-27 09:00:07

这听起来很像一个坏主意。

为什么不创建两个函数：一个需要密码的公共函数，一个不需要密码的私有函数。当然，公共函数可以在密码验证后调用私有函数。

像这样的事情：

public function getTokenUsingPassword($password)
{
    if ($password == $this->password) {
        return $this->getToken();
    }
    return false;
}

private function getToken()
{
    return //code that gets token
}

This sound very much like a bad idea.

Why not make two functions: One public that requires a password and one private that doesn't. The public function can, of course, call the private function after the password has been verified.

Something like this:

public function getTokenUsingPassword($password)
{
    if ($password == $this->password) {
        return $this->getToken();
    }
    return false;
}

private function getToken()
{
    return //code that gets token
}

回复收藏 0 原文

~没有更多了~