当我更改与之相关的结构时，内存分配不起作用

发布于 2025-01-20 03:58:08 字数 707 浏览 1 评论 0原文

我目前正在使用一个结构

struct Player{
   Object obj;
   int touched;
};
typedef struct Player *Player;

，这是该结构中元素的创建：

Player createPlayer(int posiX,int posiY){
    Player p;
    p=malloc(sizeof(p));
    p->obj.posi.x=posiX;
    p->obj.posi.y=posiY;
    p->obj.life=100;
    p->touched=0;
    p->obj.damage=5;
    p->obj.friend=true;
    return p;
}

这样的每个编译都完美。但是，如果我的结构中有2个元素，

struct Player{
   Object obj;
   int touched;
   int frequency;
   int lastTouch;
};
typedef struct Player *Player;

我会在执行中收到此错误消息（代码完美地编译）：

malloc（）：无效的大小（UNSORTED）中止（核心倾倒）

我不明白为什么会收到此错误消息，因为我还没有使用这两个新变量。

原文

I'm currently working with a structure

struct Player{
   Object obj;
   int touched;
};
typedef struct Player *Player;

And here's the creation of an element from this structure :

Player createPlayer(int posiX,int posiY){
    Player p;
    p=malloc(sizeof(p));
    p->obj.posi.x=posiX;
    p->obj.posi.y=posiY;
    p->obj.life=100;
    p->touched=0;
    p->obj.damage=5;
    p->obj.friend=true;
    return p;
}

Like this every compile perfectly.
But if I had 2 elements in my structure,

struct Player{
   Object obj;
   int touched;
   int frequency;
   int lastTouch;
};
typedef struct Player *Player;

I got this error message at the execution (The code compile perfectly) :

malloc(): invalid size (unsorted)
Aborted (core dumped)

I don't understand why I got this error message, because I don't use yet these two new variables.

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爱你不解释 2025-01-27 03:58:08

您可能应该按原样定义player将其定义。 Like this:

struct Player{
   Object obj;
   int touched;
};
typedef struct Player Player_t;

Then do this:

Player_t *createPlayer(int posiX,int posiY){
    Player_t *p = malloc(sizeof(Player_t));
    p->obj.posi.x=posiX;
    p->obj.posi.y=posiY;
    p->obj.life=100;
    p->touched=0;
    p->obj.damage=5;
    p->obj.friend=true;
    return p;
}

As a side note: It is never a good idea to typedef pointers as you can never know if it is a pointer or not from its name or declaration elsewhere. You should at the very least explicitly say that it is a pointer like this:

typedef struct Player *PlayerPtr;

typedef struct Player *Player_p;

Instead of defining Player as a pointer, you should probably define it as is. Like this:

struct Player{
   Object obj;
   int touched;
};
typedef struct Player Player_t;

Then do this:

Player_t *createPlayer(int posiX,int posiY){
    Player_t *p = malloc(sizeof(Player_t));
    p->obj.posi.x=posiX;
    p->obj.posi.y=posiY;
    p->obj.life=100;
    p->touched=0;
    p->obj.damage=5;
    p->obj.friend=true;
    return p;
}