有没有一种方便的方法可以多次调用一个函数而无需循环？

发布于 2025-01-19 19:44:40 字数 574 浏览 0 评论 0原文

我目前正在制作一些代码，以随机生成一组随机日期并将其分配给矩阵。我希望随机生成n个量的日期（天和月），并将其显示在NX2矩阵中。我的代码如下如下，

function dates = dategen(N)

    month = randi(12);

    if ismember(month,[1 3 5 7 8 10 12])
        day = randi(31);
        dates = [day, month];
    elseif ismember(month,[4 6 9 11])
        day = randi(30);
        dates = [day, month];
    else
        day = randi(28);
        dates = [day, month];
    end

end

例如，如果我打电话给该函数，正如

output = dategen(3)

我期望的2x3矩阵中的3个日期一样。但是，我不确定该怎么做。我相信我需要将n包括在某个地方的功能中，但我不确定在哪里或如何。任何帮助将不胜感激。

原文

I am currently making some code to randomly generate a set of random dates and assigning them to a matrix. I wish to randomly generate N amount of dates (days and months) and display them in a Nx2 matrix. My code is as follows

function dates = dategen(N)

    month = randi(12);

    if ismember(month,[1 3 5 7 8 10 12])
        day = randi(31);
        dates = [day, month];
    elseif ismember(month,[4 6 9 11])
        day = randi(30);
        dates = [day, month];
    else
        day = randi(28);
        dates = [day, month];
    end

end

For example if I called on the function, as

output = dategen(3)

I would expect 3 dates in a 2x3 matrix. However, I am unsure how to do this. I believe I need to include N into the function somewhere but I'm not sure where or how.
Any help is greatly appreciated.

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俯瞰星空 2025-01-26 19:44:40

您可以使用逻辑索引来完成此操作，如下所示：

function dates = dategen(N)

months = randi(12, 1, N);

days = NaN(size(months)); % preallocate
ind = ismember(months, [1 3 5 7 8 10 12]);
days(ind) = randi(31, 1, sum(ind));
ind = ismember(months, [4 6 9 11]);
days(ind) = randi(30, 1, sum(ind));
ind = ismember(months, 2);
days(ind) = randi(28, 1, sum(ind));

dates = [months; days];

end

You can do it using logical indexing as follows:

function dates = dategen(N)

months = randi(12, 1, N);

days = NaN(size(months)); % preallocate
ind = ismember(months, [1 3 5 7 8 10 12]);
days(ind) = randi(31, 1, sum(ind));
ind = ismember(months, [4 6 9 11]);
days(ind) = randi(30, 1, sum(ind));
ind = ismember(months, 2);
days(ind) = randi(28, 1, sum(ind));

dates = [months; days];

end

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