JavaScript数组计数和删除零

Question

我有一个数组 let test = [0,0,0,0,0,0,0,0,0,0,3,4,5,6,3,0, 0,0,0,4,6,7]

我需要从起点计算零的数量，在本例中为“9”，直到值 3

下一步想要只删除前九个条目。数组其余部分中的剩余零必须保留。

预期结果

计数 = 9 让测试= [3,4,5,6,3,0,0,0,0,4,6,7]

Answer 1

首先，示例的结果应该是 Count = 10，因为 0 有 10 个。

我想您想定义一个函数来获取结果。那可以是：

const func = (arr) => {
    let count = 0
    for (let i in arr) {
        if (arr[i] != 0) {
            break
        }
        count++
    }
    return [count, arr.slice(count)]
}

// Test:
const array = [0,0,0,0,0,0,0,0,0,0,3,4,5,6,3,0,0,0,0,4,6,7]
console.log(`Count = ${func(array)[0]}, Array = ${func(array)[1]}`)
// Result should be Count = 10, Array = [3,4,5,6,3,0,0,0,0,4,6,7]

Answer 2

请尝试以下代码：

function firstZeros(r) {

    var c = 0,s=true,nr=[];
    for(let ri of r){
        if(s && ri==0){
            c++;
        }else{
            s=false;        
            nr.push(ri);
        }
    }
    
    return {'count':c,'data':nr};
}


let test = [0,0,0,0,0,0,0,0,0,3,4,5,6,3,0,0,0,0,4,6,7];

let res = firstZeros(test);

console.log('Count='+res.count);
console.log('Test='+res.data);

谢谢