REGEX-获取逗号分隔的列表允许逗号之前 /之后的空间

Question

I try to extract an images array/list from a commit message:

String commitMsg = "#build #images = image-a, image-b,image_c, imaged , image-e #setup=my-setup fixing issue with px"

I want to get a list that contains:

["image-a", "image-b", "image_c", "imaged", "image-e"]

NOTES:

A) should allow a single space before/after the comma (,)

B) ensure that #images = exists but exclude it from the group

C) I also searching for other parameters like #build and #setup so I need to ignore them when looking for #images

What I have until now is:

/(?i)#images\s?=\s?<HERE IS THE MISSING LOGIC>/

我使用Find（）方法：

def matcher = commitMsg =~ /(?i)#images\s?=\s?([^,]+)/ 

if(matcher.find()){
    println(matcher[0][1])
}

Answer 1

您可以使用

(?i)(?:\G(?!^)\s?,\s?|#images\s?=\s?)(\w+(?:-\w+)*)

regex demo 。 详细信息：

• （？i） -
• 上的案例不敏感模式（？ ？= \ s？） - 上一个正则匹配的末端和两端的单个可选空间的逗号，或 #images string和a = char在两端上都带有单个可选的空格
• （\ w+（？： - \ w+）*） - 组1：一个或多个单词chars，然后以的零或更多重复 - 和一个或多个字符。

请参阅a groovy demo ：

String commitMsg = "#build #images = image-a, image-b,image_c, imaged , image-e #setup=my-setup fixing issue with px"
def re = /(?i)(?:\G(?!^)\s?,\s?|#images\s?=\s?)(\w+(?:-\w+)*)/
def res = (commitMsg =~ re).collect { it[1] }
print(res)

output：

[image-a, image-b, image_c, imaged, image-e]

an 替代性凹槽代码：

String commitMsg = "#build #images = image-a, image-b,image_c, imaged , image-e #setup=my-setup fixing issue with px"
def re = /(?i)(?:\G(?!^)\s?,\s?|#images\s?=\s?)(\w+(?:-\w+)*)/
def matcher = (commitMsg =~ re).collect()
for(m in matcher) {
    println(m[1])
}