检查时间和日期的功能？

Question

我想编写一个程序，以检查一周的时间和一天，然后根据该信息为能量管理系统开关操作模式。该计划需要在整天每天连续运行和检查日期和时间。这是我最挣扎的第一部分。根据以前的工作，我尝试了下面的解决方案，但是我不确定这是执行此操作的最有效或正确的方法。我想知道是否有更好的方法来执行此操作。

#SE_v1_algorithm
#this algorithm is meant to modify the times at which the system charges and 
#discharges each day

import time
import datetime
import schedule
import os

exec(open("filename").read()) #this line runs another Python file that gives me 
#access to APIs to change operation mode to shifting energy mode

curr_day = datetime.today().weekday()

if curr_day == 5 #Saturday
    #this section of the code checks if the time is within 9:00 and 13:00; if it 
    #is, the battery discharges
    time_start = datetime.time(9,0,0)
    time_end = datetime.time(13,0,0)
    
    def time_in_range(time_start, time_end, x):
    
    if time_start <= time_end:
        return time_start <= x <= time_end
    else:
        return time_start <= x or x <= time_end
    #set to discharging (O2)
elif curr_day == 6
    time_start = datetime.time(7,0,0)
    time_end = datetime.time(13,0,0)
    
    def time_in_range(time_start, time_end, x):
    #there will be a function here to set a switch on or off for a connected system
    if time_start <= time_end:
        return time_start <= x <= time_end
    else:
        return time_start <= x or x <= time_end
    #set to discharging (O2)
else 
    time_start = datetime.time(9,30,0)
    time_end = datetime.time(15,30,0)
    
    def time_in_range(time_start, time_end, x):
    #there will be a function here to set a switch on or off for a connected system
    if time_start <= time_end:
        return time_start <= x <= time_end
    else:
        return time_start <= x or x <= time_end
    #set to discharging (O2)