SNMP 陷阱侦听器抛出异常 nullReferenceException

发布于 2025-01-19 07:27:02 字数 1241 浏览 1 评论 0原文

我正在使用C＃中的SNMP库创建SNMP陷阱侦听器。我使用以下代码接收陷阱，

try
        {
            lst = new Listener();
            lst.AddBinding(new IPEndPoint(IPAddress.Any, 162));  
            lst.MessageReceived += Listener_MessageReceived;
            lst.StartAsync();
        }
        catch (Exception ex)
        {      
        }   
private static void Listener_MessageReceived(object sender, MessageReceivedEventArgs e)
    {
        // SNMP trap recived Here.
        File.AppendAllText("c:/temp/servicelog.log", "Version :" + e.Message.Version + "\n");
        File.AppendAllText("c:/temp/servicelog.log", "Version :" + e.Message.Scope.Pdu.Variables[4].Data.ToString() + "\n");
       
    }

然后将其作为服务运行，然后使用陷阱模拟器发送TRPA。以下是我在日志文件中获得的输出。

处理：输入。 handlemessage system.collections.generic.list`1 [lexm.sharpsnmplib.messaging.isnmpmessage]版本：v2*

当我调试时，它会出现以下错误

我还得到以下

原文

I am creating an SNMP Trap Listener using SNMP Library in c#. I used the following code to receive traps

try
        {
            lst = new Listener();
            lst.AddBinding(new IPEndPoint(IPAddress.Any, 162));  
            lst.MessageReceived += Listener_MessageReceived;
            lst.StartAsync();
        }
        catch (Exception ex)
        {      
        }   
private static void Listener_MessageReceived(object sender, MessageReceivedEventArgs e)
    {
        // SNMP trap recived Here.
        File.AppendAllText("c:/temp/servicelog.log", "Version :" + e.Message.Version + "\n");
        File.AppendAllText("c:/temp/servicelog.log", "Version :" + e.Message.Scope.Pdu.Variables[4].Data.ToString() + "\n");
       
    }

I run this as a service and then I send trpas using Trap Simulator. The following is the output I got in log file.