从总行到其他多行的拆分值,直到总和达到总行的值
CREATE TABLE inbound (
id SERIAL PRIMARY KEY,
campaign VARCHAR,
expected_inbound_date DATE,
expected_inbound_quantity DECIMAL,
received_inbound_quantity DECIMAL
);
INSERT INTO inbound
(campaign, expected_inbound_date, expected_inbound_quantity, received_inbound_quantity)
VALUES
('C001', '2022-05-03', '500', '0'),
('C001', '2022-05-03', '800', '0'),
('C001', '2022-05-03', '400', '0'),
('C001', '2022-05-03', '200', '0'),
('C001', NULL, '0', '700'),
('C002', '2022-08-20', '3000', '0'),
('C002', '2022-08-20', '5000', '0'),
('C002', '2022-08-20', '2800', '0'),
('C002', NULL, '0', '4000');
预期结果
campaign | expected_inbound_date | expected_inbound_quantity | split_received_inbound_quantity
---------|------------------------|-----------------------------|----------------------------------
C001 | 2022-05-03 | 200 | 200
C001 | 2022-05-03 | 400 | 400
C001 | 2022-05-03 | 500 | 100
C001 | 2022-05-03 | 800 | 0
C001 | | | 700
---------|------------------------|-----------------------------|----------------------------------
C002 | 2022-08-20 | 3.800 | 3.800
C002 | 2022-08-20 | 5.000 | 200
C002 | 2022-08-20 | 2.800 | 0
C002 | | | 4.000
我想拆分 received_inbound_quantity
到 expected_inbound_quantity
的每一行,直到达到 received_inbound_quantity
的总和。
SELECT
i.campaign AS campaign,
i.expected_inbound_date AS expected_inbound_date,
i.expected_inbound_quantity AS expected_inbound_quantity,
i.received_inbound_quantity AS split_received_inbound_quantity
FROM inbound i
GROUP BY 1,2,3,4
ORDER BY 1,2,3,4;
我不知道如何实现这一目标。
你有什么想法吗?
CREATE TABLE inbound (
id SERIAL PRIMARY KEY,
campaign VARCHAR,
expected_inbound_date DATE,
expected_inbound_quantity DECIMAL,
received_inbound_quantity DECIMAL
);
INSERT INTO inbound
(campaign, expected_inbound_date, expected_inbound_quantity, received_inbound_quantity)
VALUES
('C001', '2022-05-03', '500', '0'),
('C001', '2022-05-03', '800', '0'),
('C001', '2022-05-03', '400', '0'),
('C001', '2022-05-03', '200', '0'),
('C001', NULL, '0', '700'),
('C002', '2022-08-20', '3000', '0'),
('C002', '2022-08-20', '5000', '0'),
('C002', '2022-08-20', '2800', '0'),
('C002', NULL, '0', '4000');
Expected Result
campaign | expected_inbound_date | expected_inbound_quantity | split_received_inbound_quantity
---------|------------------------|-----------------------------|----------------------------------
C001 | 2022-05-03 | 200 | 200
C001 | 2022-05-03 | 400 | 400
C001 | 2022-05-03 | 500 | 100
C001 | 2022-05-03 | 800 | 0
C001 | | | 700
---------|------------------------|-----------------------------|----------------------------------
C002 | 2022-08-20 | 3.800 | 3.800
C002 | 2022-08-20 | 5.000 | 200
C002 | 2022-08-20 | 2.800 | 0
C002 | | | 4.000
I want to split the received_inbound_quantity
to each row of the expected_inbound_quantity
until the total of the received_inbound_quantity
is reached.
SELECT
i.campaign AS campaign,
i.expected_inbound_date AS expected_inbound_date,
i.expected_inbound_quantity AS expected_inbound_quantity,
i.received_inbound_quantity AS split_received_inbound_quantity
FROM inbound i
GROUP BY 1,2,3,4
ORDER BY 1,2,3,4;
I have no clue how to achieve this.
Do you have any idea?
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我想出了以下内容:
这是一个 db fiddle。
这个想法是将当前行之前的行的累积总和计算为
cum_sum
,然后选择较小的值:received_inbound_quantity
的总和减去cum_sum
code> 或expected_inbound_date
。避免值 < 0,我用过greatest
。I came up with the following:
Here is a db fiddle.
The idea is to calculate the cumulative sum of rows preceding the current row as
cum_sum
and then to pick whatever is less: the sum ofreceived_inbound_quantity
minus thecum_sum
or theexpected_inbound_date
. To avoid values < 0, I've usedgreatest
.关于答案,此问题解决此问题的另一种方法,该问题也可以在
Redshift
中工作:db-fiddle
With reference to the answer in this question an alternative way to solve the issue which is also working in
redshift
:DB-Fiddle